Question

我能够为一百万条记录成功生成一个大型xml文件使用以下代码。

cmd.CommandText = "SELECT PARTNER_NO FROM T1 WHERE YEAR LIKE '%2011-2012%'";  
XmlWriter myWriter = XmlWriter.Create("C:/Test/BookInfo.xml")  
myWriter.WriteStartDocument(true); 
using(OracleDataReader reader = cmd.ExecuteReader(CommandBehavior.CloseConnection))  
  {  
    reader.FetchSize = reader.RowSize * 5000;  
    myWriter.WriteStartElement("master_table");
    while(reader.Read())
      {  
         myWriter.WriteStartElement("partner");  
         myWriter.WriteElementString("partner_no", reader[0].ToString());  
         myWriter.WriteElementString("id","0008");  
         myWriter.WriteEndElement();  
      }  
 }  

 myWriter.WriteEndDocument();  
 myWriter.Flush();  
 myWriter.Close();  
 cmd.Dispose()

这是我的xml看起来的样子： enter image description here

我现在有了一个新的要求，即根据行数生成多个10,000个记录的xml文件。有关于此的任何指示？我该怎么办呢？这需要在c＃

上完成

Answer 1

您可以在单个SQL调用中执行此操作：

SQL> SELECT XMLSERIALIZE(CONTENT xmlelement("MASTER_TABLE",
  2                                  xmlagg(xmlelement("PARTNER",
  3                                                    XMLELEMENT("PARTNER_NO",
  4                                                               partner_no),
  5                                                    XMLELEMENT("ID", '0008')
  6                                                    )
  7                                        ))
  8                       INDENT) xmltxt
  9    FROM t1
 10   GROUP BY CEIL(ROWNUM/2)-- replace 2 by 10000
 11  ;

XMLTXT
-------------------------------------------------------------------------------
<MASTER_TABLE>
  <PARTNER>
    <PARTNER_NO>00001</PARTNER_NO>
    <ID>0008</ID>
  </PARTNER>
  <PARTNER>
    <PARTNER_NO>00034</PARTNER_NO>
    <ID>0008</ID>
  </PARTNER>
</MASTER_TABLE>
<MASTER_TABLE>
  <PARTNER>
    <PARTNER_NO>00046</PARTNER_NO>
    <ID>0008</ID>
  </PARTNER>
  <PARTNER>
    <PARTNER_NO>00052</PARTNER_NO>
    <ID>0008</ID>
  </PARTNER>
</MASTER_TABLE>

进一步阅读：

如何基于rowcount生成多个xml文件

1 个答案: