Question

如何使用SSIS表达式获取上周五的日期？使用以下表达式：

RIGHT("0" + (DT_WSTR, 2)  MONTH(dateadd("d", -1, getdate())), 2) 
+ RIGHT("0" + (DT_WSTR, 2) DAY(dateadd("d", -1, getdate())), 2)
+ RIGHT("1"+(DT_WSTR, 4)  YEAR(dateadd("d", -1, getdate())),2)+ ".csv"

上述表达式的输出为021014.csv

Answer 1

这也可以使用：

      @[User::Destination] + "_"+ (DT_WSTR,20)
     (
     DATEPART("dw",GETDATE())==1? RIGHT("0"+(DT_WSTR,2)Month (DATEADD ("D", -  1        GETDATE()) ),  2)
     +
     RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-1,GETDATE())),2)
     +
     RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2) 
     :
     DATEPART("dw",GETDATE())==2? RIGHT("0"+(DT_WSTR,2)    Month(DATEADD("D",-1,GETDATE())),2)   
    +
     RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-2,GETDATE())),2)
    +
    RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2) 
    :
    DATEPART("dw",GETDATE())==3? RIGHT("0"+(DT_WSTR,2)    >Month(DATEADD("D",-1,GETDATE())),2)
    +
    RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-3,GETDATE())),2)
    +
    RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2) 
    :
    DATEPART("dw",GETDATE())==4? RIGHT("0"+(DT_WSTR,2)    >Month(DATEADD("D",-1,GETDATE())),2)
     +
     RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-4,GETDATE())),2)
     +
     RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2) 
     :
     DATEPART("dw",GETDATE())==5? RIGHT("0"+(DT_WSTR,2)    >Month(DATEADD("D",-1,GETDATE())),2)
    +
     RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-5,GETDATE())),2)
     +
     RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2) 
     :
     DATEPART("dw",GETDATE())==6? RIGHT("0"+(DT_WSTR,2)Month (DATEADD("D",-1,GETDATE())),2)
      +
     RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-6,GETDATE())),2)
      +
      RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2)
      :
      DATEPART("dw",GETDATE())==7? RIGHT("0"+(DT_WSTR,2)    >Month( DATEADD(" D",-1,   GETDATE()     )),2)
        +
       RIGHT ("0"+(DT_WSTR,2)DAY(DATEADD("D",-7,GETDATE())),2)
        + 
        RIGHT("1"+(DT_WSTR,4)YEAR(DATEADD("D",-1,GETDATE())),2)
        : "" )
         +".csv"

Answer 2

这是使用T-SQL，您仍然需要转换为SSIS。这更像暗示了一个答案。但无法将其纳入评论。

DECLARE @CurrentDate DATE = '02/15/2014' --Saturday
--Returns Date for Friday that was last week. When current date is Saturday will return Friday that was 1 week ago.
SELECT DATEADD(dd,-DATEPART(weekday,@CurrentDate)-1,@CurrentDate)   --Output: 2014-02-07
--Returns Date for most recent Friday.
SELECT  DATEADD(dd,-(DATEPART(weekday,@CurrentDate)%7+1),@CurrentDate)  --Output: 2014-02-14

SET @CurrentDate = '02/11/2014' --Tuesday
SELECT DATEADD(dd,-DATEPART(weekday,@CurrentDate)-1,@CurrentDate)   --Output: 2014-02-07
SELECT  DATEADD(dd,-(DATEPART(weekday,@CurrentDate)%7+1),@CurrentDate)  --Output: 2014-02-07

你需要弄清楚你星期五的要求是什么，是上周末的星期五，还是上个星期五，而是本周或之前的星期五。

SSIS表达上周五的日期

2 个答案: