Question

我需要删除以Windows批处理脚本中的字符串中的单词开头的所有内容。例如，如果我有字符串：

This is my line delete from here.

我想删除以delete一词开头的所有内容，我需要获取：

This is my line.

我试过这个：

set line="This is my line delete from here"
set word="delete"
set delete="!word!*";
set line=!line:%delete%=!

它无法正常运行，我已经激活延迟扩展，我不确定是否：“set line =！line：％delete％=！”作品。我也试过这个“set line =！line :! delete！=！”但也不起作用。我是批处理脚本的新手。

更新：在循环中，我只能进行延迟扩展，并且此代码不起作用：

@ECHO OFF

setlocal
for /F "delims= " %%A in (temp.txt) do ( 
    set "line=This is my line delete from here"
    ECHO original:%line%:
    set "word=delete"
    CALL set "delete=%%line:*%word%=%%"
    ECHO delete the "%word%%delete%" part
    CALL set "line=%%line:%word%%delete%=%%"
    ECHO final   :%line%:
)
endlocal

输出：

original::
=%" was unexpected at this time.
delete the "" part
=%" was unexpected at this time.
final   ::

但是如果从上面的代码中删除for，则输出为：

original:This is my line delete from here:
delete the "delete from here" part
final   :This is my line :

我的问题是如何在循环中做同样的事情，延迟扩展，就像正常扩展一样。换句话说，我需要在替换表达式内部和外部的两个变量的后期扩展（设置“delete =！line：*！word！=！”，不起作用）。我找不到任何相关的文档。感谢。

Answer 1

@ECHO OFF
SETLOCAL
set "line=This is my line delete from here"
ECHO original:%line%:
set "word=delete"
CALL set "delete=%%line:*%word%=%%"
ECHO delete the "%word%%delete%" part
CALL set "line=%%line:%word%%delete%=%%"
ECHO final   :%line%:

GOTO :EOF

这应该会显示步骤。

首先，删除包含该单词的部分。然后删除单词和剩余行（delete）

注意引号的位置 - 控制set而不是分配的值。

Answer 2

我已阅读this以及基于Magoo答案的更新代码：

@ECHO OFF

setlocal
for /F "delims= " %%A in (temp.txt) do ( 
    set "line=This is my line delete from here"
    set "word=delete"
    echo line is: !line!
    for /f "delims=" %%a in ("!word!") do set delete=!line:*%%a=!
    echo delete is: !delete!
    for /f "delims=" %%a in ("!word!!delete!") do set line=!line:%%a=!
    echo line is: !line!
)
endlocal

批量替换字符串中的正则表达式

2 个答案: