Question

我想创建一个页面，我必须显示特定ID的记录，但它显示我的错误

注意：未定义的变量：第82行的mysqli。

致命错误：在第82行的非对象上调用成员函数query（）。

这是程序的PHP代码。

$con=mysqli_connect("XXXX","XXXX","XXXX","XXXX");
if (mysqli_connect_errno()) 
    echo "Failed to connect to MySQL: " . mysqli_connect_error();

$id = $_GET['id'];
$sql = "SELECT * FROM details WHERE cat_id = $id";
$result = mysqli_query($con,$sql); //line #82
$row = mysqli_fetch_array($result);

while($row = mysqli_fetch_array($result)){
  $id = $row['cat_id'];
  echo "<tr>";
  echo "<td><a href='detail.php?id=$id' >" . $row['cat_name'] . "</a></td>";
  echo "</tr>";
}
echo "<table>";

echo    "<tr>";
echo      "<th>name</th>";
echo      "<th>address</th>";
echo      "<th>phone</th>";
echo      "<th>uan</th>";
echo      "<th>location</th>";
echo    "</tr>";

mysqli_close($con);

Answer 1

你没有像这样正确地循环记录：

$id = $_GET['id'];
$result = mysqli_query($con,"SELECT * FROM details WHERE cat_id = $id");
echo "<table>
<tr>
<th>name</th>
<th>address</th>
<th>phone</th>
<th>uan</th>
</tr>";
while($row = mysqli_fetch_array($result)){
  echo "<tr>";
    echo "<td>" . $row['name'] . "</td>";
      echo "<td>" . $row['address'] . "</td>";
      echo "<td>" . $row['phone'] . "</td>";
      echo "<td>" . $row['uan'] . "</td>";
    echo "</tr>";
}

Answer 2

$ con = mysqli_connect（“XXXX”，“XXXX”，“XXXX”，“XXXX”）; if（mysqli_connect_errno（）） {echo“无法连接到MySQL：”。 mysqli_connect_error（）;} $ id = $ _ GET ['id']; $ sql =“SELECT * FROM details WHERE cat_id = $ id”; $ result = mysqli_query（$ con，$ sql）; // line＃82 $ row = mysqli_fetch_array（$ result）; echo“”; echo“”; echo“name”; echo“address”; echo“phone”; echo“uan”; echo“location”; echo“” ;而（$行= mysqli_fetch_array（$结果）） {$ id = $ row ['cat_id']; echo“”;回声“”。 $ row ['cat_name']。 “”; echo“”; } mysqli_close（$ CON）;

我想获取多行，在获取行中有错误？

2 个答案: