ValidationMessage和ModelState.AddModelError不起作用

时间:2014-02-11 10:26:40

标签: asp.net-mvc asp.net-mvc-4 modelstate

我想做cusotm验证并在验证失败时返回false和show message。

在控制器下面,代码用于将发布的数据提交到数据库。

       [HttpPost]
       public JsonResult SubmitDa(IList<AdViewModel> s, String section)
           {

            ...........
              ..........


            ModelState.AddModelError("MessageError", "Please enter AttendanceDate");

             JSONSubmit r = new JSONSubmit();
            r.ErrorCount = iError;
            r.errors = errors;

           return Json(r, JsonRequestBehavior.AllowGet);

       }

以下是视图文件(cshtml)中的代码

       @Html.ValidationMessage("MessageError")  
        .....  

       $.AJAX call to `SubmitDa` controller's method.

消息未出现在“MessageError”验证消息中。请告诉我这里有什么问题。

由于

1 个答案:

答案 0 :(得分:2)

如果您想使用modelstate进行错误,则不应该发送JSON响应。说过你可以通过控制器只在成功的情况下返回JSON来处理它,并且页面处理响应的方式不同

IE:

[HttpPost]
public ActionResult SubmitDa(IList<AdViewModel> s, String section)
{

        ...........
          ..........


        ModelState.AddModelError("MessageError", "Please enter AttendanceDate");

         JSONSubmit r = new JSONSubmit();
        r.ErrorCount = iError;
        r.errors = errors;
       if (r.ErrorCount != 0)
           return Json(r, JsonRequestBehavior.AllowGet);

       return View("ViewName", s); // <-- just return the model again to the view,
                                   //     complete with modelstate!
}
页面上的

类似于:

<script>

$("#buttonId").click({
   $.ajax({
     type: "POST",
     url: "PostBackURL",
     data: $("#formID").serialize(),
     success: function (response){
       //test for a property in the JSON response
       if(response.ErrorCount && response.ErrorCount == 0) 
       {
           //success! do whatever else you want with the response

       } else {
          //fail - replace the HTML with the returned response HTML.
          var newDoc = document.open("text/html", "replace");
          newDoc.write(response);
          newDoc.close();
       }

     }
   });
});

</script>