Question

如何将以下SQL转换为JPQL？

SELECT *
FROM SSSRC.NAME_TEST nameTest
LEFT JOIN TTREFERENCE.LOCATION location
ON nameTest.place= location.location_name WHERE nameTest.gender = 'Male'
AND nameTest.age= '50'
AND nameTest.name IS NOT NULL 
ORDER BY nameTest.sortby ,location.location_order;

我像这样转换

"SELECT nameTest FROM NameTest nameTest, LEFT JOIN Location location ON nameTest.place = location.location_name WHERE nameTest.age= '50' and nameTest.gender = 'Male' and nameTest.name IS NOT NULL ORDER BY nameTest.sortby ,location.location_order";

但是

它无法正常发出以下错误

Exception in thread "main" <openjpa-2.0.0-r422266:935683 nonfatal user error> org.apache.openjpa.persistence.ArgumentException: "Encountered "location" at character 66, but expected: [",", "GROUP", "HAVING", "INNER", "JOIN", "LEFT", "ORDER", "WHERE", <EOF>]." while parsing JPQL "SELECT nameTest FROM PrintRequest nameTest, LEFT JOIN LOCATION location ON nameTest.place = location.location_name WHERE nameTest.age= '50' and nameTest.gender = 'Male' and nameTest.name IS NOT NULL ORDER BY nameTest.sortby ,location.location_order";. See nested stack trace for original parse error.
      at org.apache.openjpa.kernel.jpql.JPQLParser.parse(JPQLParser.java:51)
      at org.apache.openjpa.kernel.ExpressionStoreQuery.newCompilation(ExpressionStoreQuery.java:150)
      at org.apache.openjpa.kernel.QueryImpl.newCompilation(QueryImpl.java:670)
      at org.apache.openjpa.kernel.QueryImpl.compilationFromCache(QueryImpl.java:652)
      at org.apache.openjpa.kernel.QueryImpl.compileForCompilation(QueryImpl.java:618)
      at org.apache.openjpa.kernel.QueryImpl.compileForExecutor(QueryImpl.java:680)
      at org.apache.openjpa.kernel.QueryImpl.compile(QueryImpl.java:587)
      at org.apache.openjpa.persistence.EntityManagerImpl.createQuery(EntityManagerImpl.java:985)

Answer 1

试试这个：

"SELECT nameTest
FROM NameTest as nameTest
LEFT JOIN Location
ON nameTest.place = Location.location_name
WHERE nameTest.age = '50' and
nameTest.gender = 'Male' and
nameTest.name IS NOT NULL
ORDER BY nameTest.sortby, Location.location_order";

Answer 2

你可以尝试这段代码：

    "SELECT nameTest FROM NameTest nameTest 

    LEFT JOIN Location location ON nameTest.place = location.location_name 

    WHERE nameTest.age= '50' and nameTest.gender = 'Male' and nameTest.name IS NOT NULL 

    ORDER BY nameTest.sortby, location.location_order";

注意ON子句在JPA 2.1中定义并在EclipseLink 2.4中受支持，对于hibernate支持，请检查以下答案：https://stackoverflow.com/a/5220962/1047582

在我看来，你的JPA不支持ON子句。对于简单的LEFT JOIN，您需要更改您的实体。例如，NameTest类有一个Location元素：

public class NameTest{

  @JoinColumn(name = "locationId", referencedColumnName = "location")
  @ManyToOne()
  Location location;

(...)
}

在这种情况下，JPQL看起来像：

SELECT nameTest FROM NameTest nameTest 

        LEFT JOIN nameTest.location location 

        WHERE nameTest.age= '50' and nameTest.gender = 'Male' and nameTest.name IS NOT NULL 

        ORDER BY nameTest.sortby, location.location_order

如何将下面的SQL转换为JPQL？

2 个答案: