Question

这是我的代码

 $rQuery="SELECT * FROM rowManagr WHERE id=0";
    $rResult = $mysqli->query($rQuery)or die($mysqli->error.__LINE__);
    while($row = $rResult->fetch_assoc())
    {

        $rowQuery='SELECT * FROM row_vid WHERE rowid='.$row['rowid'];
        $rowResult = $mysqli->query($rowQuery)or die($mysqli->error.__LINE__);

        while($rowHome = $rowResult->fetch_assoc())
        {
            if($rowHome['showid']!=0 )
            {

                 $json[] = array(....);


            }


                elseif($rowHome['season_id']!=0){
                   $json[] = array(....);

               }
               elseif($rowHome['showid']==0 && $rowHome['season_id']==0){
                $json[] = array(....); 


               }





    }

$jsondata[$row['rowname']]=$json;
$g['responses']= $jsondata;
    }



     $jsons = json_encode($g);
     echo $jsons;

此代码的输出是（示例）

{"responses":{
  "Seasons":[
     {"1a"},
     {"2a"},
     {"3a"},
     {"4a"}
  ],
  "Other Show":[
     {"1a"},
     {"2a"},
     {"3a"},
     {"4a"},
     {"1b"},
     {"2b"},
     {"3b"},
     {"4b"}
  ],
  "Videos":[
     {"1a"},
     {"2a"},
     {"3a"},
     {"4a"},
     {"1b"},
     {"2b"},
     {"3b"},
     {"4b"},
     {"1a"},
     {"2a"},
     {"3a"},
     {"4a"},
     {"1c"},
     {"2c"},
     {"3c"},
     {"4c"}
  ]

} }

季节，其他节目，视频包含4个结果，但在输出季节被复制到其他节目，季节和其他节目被复制到视频。

实际输出应为

{
   "responses":{
      "Seasons":[
         {"1a"},
     {"2a"},
     {"3a"},
     {"4a"}
      ],
      "Other Show":[
         {"4a"},
     {"1b"},
     {"2b"},
     {"3b"},
     {"4b"}

      ],
      "Videos":[
         {"1c"},
     {"2c"},
     {"3c"},
     {"4c"}
      ]
   }
}

由于

Answer 1

请查看我的代码。

它将为您提供在示例中定义的代码。

这也是一个例子。

<?php
$mysqli = mysqli_connect('localhost','root','','DBName');
    $json = '{ responses {"Seasons:["';
    $rQuery = "SELECT * FROM TBL_NAME";
    $rResult = $mysqli->query($rQuery)or die($mysqli->error.__LINE__);
    while($row = $rResult->fetch_assoc())
    {
        $json .= "{" . $row['name'] . "}" ;
    }
    $json .= "]}}";
    echo $json ;
?>

Answer 2

只需在内部while循环之前初始化数组$jon：

while($row = $rResult->fetch_assoc()) {
    $rowQuery='SELECT * FROM row_vid WHERE rowid='.$row['rowid'];
    $rowResult = $mysqli->query($rowQuery)or die($mysqli->error.__LINE__);

    // init $json
    $json = array();

    while($rowHome = $rowResult->fetch_assoc()) {
        if($rowHome['showid']!=0 ) {
             $json[] = array(....);
        }
        ...

Answer 3

使用break;退出while循环，并使用else if结构代替nested if。

Php循环问题

3 个答案: