Foreach循环不适用于php中的sqlite

时间:2014-02-11 06:14:24

标签: php database sqlite foreach while-loop

我想在下面的代码中使用foreach进行循环而不是while循环。但由于某种原因,foreach循环不能像我预期的那样工作。请帮我解决这个问题。

class MyDB extends SQLite3
 {
  function __construct()
  {
     $this->open('test.db');
  }
  }
  $db = new MyDB();
  if(!$db){
  echo $db->lastErrorMsg();
  } else {
  echo "Opened database successfully\n";
  }

  $sql =<<<EOF
  SELECT * from COMPANY;
  EOF;
  $ret = $db->query($sql);
  $newArray = array_chunk($links['data'], 12, false);
  while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
  echo "ID = ". $row['ID'] . "\n";
  echo "NAME = ". $row['NAME'] ."\n";
  echo "ADDRESS = ". $row['ADDRESS'] ."\n";
  echo "SALARY =  ".$row['SALARY'] ."\n\n";
  }
  echo "Operation done successfully\n";
  $db->close();

这是我使用的代码。

$ret = $db->query($sql);
$value = $ret->fetchArray(SQLITE3_ASSOC);
foreach($value as $row){
  echo "ID = ". $row['ID'] . "\n";
  echo "NAME = ". $row['NAME'] ."\n";
  echo "ADDRESS = ". $row['ADDRESS'] ."\n";
  echo "SALARY =  ".$row['SALARY'] ."\n\n";
}
echo "Operation done successfully\n";
$db->close();

3 个答案:

答案 0 :(得分:1)

也许我迟到了,但无论如何

foreach 样本

    foreach ($ret->fetchArray(SQLITE3_ASSOC) as $row) {
      echo "<pre>";
      $array[] = $row;
    }

    echo $array[0] ."\n";
    echo $array[1] ."\n";
    echo $array[2] ."\n";

答案 1 :(得分:0)

这段代码对我有用。

  $sql =<<<EOF
  SELECT * from COMPANY;
  EOF;
  $ret = $db->query($sql);
  while($row = $ret->fetchArray(SQLITE3_ASSOC) ){
  $data[]=array('id'=>$row['ID'],'name'=>$row['NAME'],'address'=>$row['ADDRESS'],'salary'=>$row['SALARY']);
  }
  echo "Operation done successfully\n";
  $db->close();
  foreach($data as $val){
 echo $val['id'].'<br>'.$val['address'].'<br>'.$val['salary'].'<br>';
}

答案 2 :(得分:0)

我认为不适用于 SQlite3 类,但使用 PDO...

$db = new PDO('sqlite:(your path)test.db');
$sql =<<<EOF
SELECT * from COMPANY;
EOF;

$ret = $db->query($sql);

foreach($ret as $row){
  echo "ID = ". $row['ID'] . "\n";
  echo "NAME = ". $row['NAME'] ."\n";
  echo "ADDRESS = ". $row['ADDRESS'] ."\n";
  echo "SALARY =  ".$row['SALARY'] ."\n\n";
}

SQlite3 类也不适用于 Laravel。 PDO 有效。我使用的是 PHP 8 和 Laravel 8。

我在哪里找到的:https://www.a2hosting.com.br/kb/developer-corner/sqlite/connect-to-sqlite-using-php