Question

import math
import sys

def calculateValues(loanAmt, numYears):
    for monthlyRate in range (4, 9):
        monthlyRate = monthlyRate / 100
        monthlyPayment = loanAmt * monthlyRate / (1 - math.pow(1 / (1 + monthlyRate), numYears * 12))
        totalPayment = monthlyPayment * numYears * 12
        return monthlyRate, monthlyPayment, totalPayment

def printPayments(monthlyRate, monthlyPayment, totalPayment, loanAmt, numYears):
    print("Rate   Monthly Payment  Total Payment")
    for monthlyRate in range (4, 9):
        calculateValues(loanAmt, numYears)
        print("{0}%     ${1:0.2f}         ${2:0.2f}".format( monthlyRate, monthlyPayment, totalPayment))

def repeat():
    question = str(input("Would you like to create a new table? (Enter y for yes): "))
    if (question == "y"):
        main()
    else:
        sys.exit()

def getPositiveFloat():
    loanAmt = int(input("Enter the amount of the loan: "))
    numYears = int(input("Enter the number of years: "))
    if (loanAmt < 0) or (numYears < 0):
        print("Please enter a positive number for both questions")
        main()
    return loanAmt, numYears

def main():
    loanAmt, numYears = getPositiveFloat()
    monthlyRate, monthlyPayment, totalPayment = calculateValues(loanAmt, numYears)
    printPayments(monthlyRate, monthlyPayment, totalPayment, loanAmt, numYears)
    repeat()

main()

当此程序运行时，monthlyRate变量（在printPayments中定义）会迭代，但calculateValues中计算的值不会迭代。我已经发现我需要将monthlyRate计算为值作为参数，但我不确定如何在没有一切破坏的情况下做到这一点。

Answer 1

代码中存在一些问题，您可以通过以下代码执行diff来轻松查看。

calculateValues：在循环中运行并在第一次迭代时返回结果
printPayments调用calculateValues但没有获取结果（这就是为什么同一行一次又一次打印
printPayments也会在循环中打印 - 这意味着有一个不需要的循环
main（）调用calculateValues然后调用printPayments - 这意味着再次调用两个for循环次数，而不保存结果

这是固定代码：

import math
import sys

def calculateValues(monthlyRate, loanAmt, numYears):
    monthlyRate = monthlyRate / 100
    monthlyPayment = loanAmt * monthlyRate / (1 - math.pow(1 / (1 + monthlyRate), numYears * 12))
    totalPayment = monthlyPayment * numYears * 12
    return monthlyRate, monthlyPayment, totalPayment

def printPayments(loanAmt, numYears):
    print("Rate   Monthly Payment  Total Payment")
    for monthlyRate in range (4, 9):
        monthlyRate, monthlyPayment, totalPayment = calculateValues(monthlyRate, loanAmt, numYears)
        print("{0}%     ${1:0.2f}         ${2:0.2f}".format(int(monthlyRate*100, monthlyPayment, totalPayment))

def repeat():
    question = str(input("Would you like to create a new table? (Enter y for yes): "))
    if (question == "y"):
        main()
    else:
        sys.exit()

def getPositiveFloat():
    loanAmt = int(input("Enter the amount of the loan: "))
    numYears = int(input("Enter the number of years: "))
    if (loanAmt < 0) or (numYears < 0):
        print("Please enter a positive number for both questions")
        main()
    return loanAmt, numYears

def main():
    loanAmt, numYears = getPositiveFloat()
    printPayments(loanAmt, numYears)
    repeat()

main()

<强>输出：

Enter the amount of the loan: 100
Enter the number of years: 20
Rate   Monthly Payment  Total Payment
4%     $4.00         $960.08
5%     $5.00         $1200.01
6%     $6.00         $1440.00
7%     $7.00         $1680.00
8%     $8.00         $1920.00
Would you like to create a new table? (Enter y for yes):

我认为你在这里计算兴趣的方式有问题：

monthlyPayment = loanAmt * monthlyRate / (1 - math.pow(1 / (1 + monthlyRate), numYears * 12))

但是这部分我会让你自己解决;）

Answer 2

如果你的代码就像你在那里键入的那样你的返回语句缩进太多

，这很容易

def calculateValues(loanAmt, numYears):
    myAnswer = []
    for monthlyRate in range (4, 9):
        monthlyRate = monthlyRate / 100
        monthlyPayment = loanAmt * monthlyRate / (1 - math.pow(1 / (1 + monthlyRate), numYears * 12))
        totalPayment = monthlyPayment * numYears * 12
        thisRound = (monthlyRate, monthlyPayment, totalPayment)
        myAnswer.append(thisRound)
    return myAnswer

在第一次迭代后，它应该看起来像你正在返回

我只是在猜测你想要每次迭代的结果，你需要将它们保存在某个容器中。我个人会将它们保存在字典中，但直到你的目标更明确才准备好

在您感觉更舒服之前，您应该考虑的一件事是在函数中添加一些打印语句，以便在每次迭代中看到值是什么

 def testFunction(somevalue):
    for x in range(0, somevalue):
        print 'hello'
    return x

y = testFunction(2)

hello
hello
>>>y
1

Answer 3

问题是你的代码第一次遇到“return”语句时，它会返回值并离开函数。看起来你在printpayments中循环遍历monthlyRate（monthlyRate = [4,5,6,7,8]）。没关系。现在，对于您的calculateValues函数，您希望将monthlyPayment和totalPayment返回给调用函数。您还需要将monthlyRate作为参数传递。

def calculateValues(monthlyRate, loanAmt, numYears):
    monthlyRate = monthlyRate / 100
    monthlyPayment = loanAmt * monthlyRate \
                / (1 - math.pow(1 / (1 + monthlyRate), numYears * 12))
    totalPayment = monthlyPayment * numYears * 12
    return (monthlyPayment, totalPayment)

def printPayments(monthlyRate, monthlyPayment, totalPayment, loanAmt, numYears):
    print("Rate   Monthly Payment  Total Payment")
    for monthlyRate in range (4, 9):
        monthlyPayment, totalPayment = calculateValues(monthlyRate, loanAmt, numYears)
        print("{0}%     ${1:0.2f}         ${2:0.2f}".format( monthlyRate, \
               monthlyPayment, totalPayment))

通常，看起来你需要做一堆阅读并思考如何在计算机编程中编写函数，特别是在程序执行期间可以看到变量的地方。这是这种阅读的潜在有用链接：

http://gettingstartedwithpython.blogspot.com/2012/05/variable-scope.html

希望这有帮助。

迭代的Python问题

3 个答案: