堆积条形图 - y轴和第一个条形之间的空间:matplotlib.pyplot

时间:2014-02-10 21:33:58

标签: python-3.x matplotlib

我刚刚开始使用matplotlib.pyplot并且有点卡住了。

使用matpltlib.pyplot文档中的示例,我使用以下代码创建了堆积条形图enter image description here

import numpy as np
import matplotlib.pyplot as plt

N = 7
OECD = (242, 244, 255, 263, 269, 276, 285)
NonOECD = (282, 328, 375, 417, 460, 501, 535)
Sum = ('524', '572', '630', '680', '729', '777', '820')
ind = np.arange(N)
width = 0.5

p1 = plt.bar(ind, NonOECD, width, color = 'r')
p2 = plt.bar(ind, OECD, width, color = 'b', bottom = NonOECD)

plt.ylabel('Quadrillion Btu')
plt.title('World Total Energy Consumption 2010 - 2040')
plt.xticks(ind+width/2., ('2010', '2015', '2020', '2025', '2030', '2035', '2040'))
plt.yticks(np.arange(0, 1001, 200))
plt.legend((p1[0], p2[0]), ('Non - OECD', 'OECD'), loc = 2, frameon = 'false')
plt.tick_params(top = 'off', bottom = 'off', right = 'off')
plt.grid(axis = 'y', linestyle = '-')

plt.show()

但是,如果第一个柱子(2010)没有正对着y轴,我宁愿这样做 我试过简单地在plt1和plt2中添加1到ind

p1 = plt.bar(ind+1, NonOECD, width, color = 'r')  
p2 = plt.bar(ind+1, OECD, width, color = 'b', bottom = NonOECD)

但是,我无法确定ticklabels的等效变化。所以,到目前为止,我所生成的只有:enter image description here

话虽如此,我可以通过使N = 8来捏造这个,在两个元组中增加额外的零第一项? OECD和NonOECD并添加空白xticklabel:

N = 8  
OECD = (0, 242, 244, 255, 263, 269, 276, 285)  
NonOECD = (0, 282, 328, 375, 417, 460, 501, 535)  
Sum = (0, '524', '572', '630', '680', '729', '777', '820')  

plt.xticks(ind+width/2., ('', '2010', '2015', '2020', '2025', '2030', '2035', 2040'))

但是,我无法使用此软糖,因为我想显示总计on top of the stacks ....

1 个答案:

答案 0 :(得分:2)

您想要使用"边距"功能。您的代码已修改:

fig = plt.figure()
ax  = fig.add_subplot(111)
# the first argument is the margin of the x-axis, the second of the y-axis
ax.margins(0.04, 0)  

p1 = ax.bar(ind, NonOECD, width, color = 'r')
p2 = ax.bar(ind, OECD, width, color = 'b', bottom = NonOECD)