有没有办法将System.Drawing.Image附加到电子邮件而不保存,然后从保存的路径中抓取它。
现在我正在创建图像并保存它。然后我发送电子邮件:
MailMessage mail = new MailMessage();
string _body = "body"
mail.Body = _body;
string _attacmentPath;
if (iP.Contains(":"))
_attacmentPath = (@"path1");//, System.Net.Mime.MediaTypeNames.Application.Octet));
else
_attacmentPath = @"path2");
mail.Attachments.Add(new Attachment(_attacmentPath, System.Net.Mime.MediaTypeNames.Application.Octet));
mail.To.Add(_imageInfo.VendorEmail);
mail.Subject = "Rouses' PO # " + _imageInfo.PONumber.Trim();
mail.From = _imageInfo.VendorNum == 691 ? new MailAddress("email", "") : new MailAddress("email", "");
SmtpClient server = null;
mail.IsBodyHtml = true;
mail.Priority = MailPriority.Normal;
server = new SmtpClient("server");
try
{
server.Send(mail);
}
catch
{
}
无论如何直接将System.Drawing.Image传递给mail.Attachments.Add()?
答案 0 :(得分:15)
您无法将Image
直接传递给附件,但只需将图片保存到MemoryStream
,然后将MemoryStream
提供给var stream = new MemoryStream();
image.Save(stream, ImageFormat.Jpeg);
stream.Position = 0;
mail.Attachments.Add(new Attachment(stream, "image/jpg"));
即可跳过文件系统。附件构造函数:
{{1}}
答案 1 :(得分:5)
理论上,您可以将Image转换为MemoryStream,然后将该流添加为附件。它会是这样的:
public static Stream ToStream(this Image image, ImageFormat formaw) {
var stream = new System.IO.MemoryStream();
image.Save(stream, formaw);
stream.Position = 0;
return stream;
}
然后您可以使用以下
var stream = myImage.ToStream(ImageFormat.Gif);
现在您已拥有该流,您可以将其添加为附件:
mail.Attachments.Add(new Attachment(stream, "myImage.gif", "image/gif" ));
参考文献: