Question

大家，我是Linux和Linux的新手。非常感兴趣编写shell脚本。这次我正在制作一张excel表。在那张excel表中会有S.No.在第1栏＆amp;第二列中的域名。我的Excel工作表中有100个域名。所以，我不想手动复制每个域名＆amp;将它们粘贴到浏览器中以检查全部。我只想编写一个shell脚本，它可以通过运行单个shell脚本将所有域打开到浏览器中。请帮帮我。我将非常感谢你。

谢谢＆amp;问候- Reetesh Chauhan

Answer 1

xls2csv会将您的xls文件转换为CSV格式。

将其移至sed以删除双引号。

使用while迭代每一行。

echo每行（l）到awk将第二个（$2）列放入$d（域名）变量。

然后将其发送到浏览器。您可以使用自己喜欢的浏览器替换lynx。 GUI浏览器的工作方式与TUI浏览器一样简单。

xls2csv domains.xls | sed -e's/"//g' | while read l; do d=`echo "$l" | awk  '{print $2}'`; lynx "$d"; done

Answer 2

你可以使用样本：help1 help2 help3

您可以使用perl：

#!/usr/bin/perl
use Spreadsheet::WriteExcel;
my $workbook = Spreadsheet::WriteExcel->new("test.xls"); 
my $worksheet = $workbook->add_worksheet();
open(FH,"<file") or die "Cannot open file: $!\n";
my ($x,$y) = (0,0);
while (<FH>){ 
 chomp;
 @list = split /\s+/,$_;
 foreach my $c (@list){
    $worksheet->write($x, $y++, $c);     
 }
 $x++;$y=0;
}
close(FH);
$workbook->close();

和python：

#!/usr/local/bin/python
# Tool to convert CSV files (with configurable delimiter and text wrap
# character) to Excel spreadsheets.
import string
import sys
import getopt
import re
import os
import os.path
import csv
from pyExcelerator import *

def usage():
  """ Display the usage """
  print "Usage:" + sys.argv[0] + " [OPTIONS] csvfile"
  print "OPTIONS:"
  print "--title|-t: If set, the first line is the title line"
  print "--lines|-l n: Split output into files of n lines or less each"
  print "--sep|-s c [def:,] : The character to use for field delimiter"
  print "--output|o : output file name/pattern"
  print "--help|h : print this information"
  sys.exit(2)

def openExcelSheet(outputFileName):
  """ Opens a reference to an Excel WorkBook and Worksheet objects """
  workbook = Workbook()
  worksheet = workbook.add_sheet("Sheet 1")
  return workbook, worksheet

def writeExcelHeader(worksheet, titleCols):
  """ Write the header line into the worksheet """
  cno = 0
  for titleCol in titleCols:
    worksheet.write(0, cno, titleCol)
    cno = cno + 1

def writeExcelRow(worksheet, lno, columns):
  """ Write a non-header row into the worksheet """
  cno = 0
  for column in columns:
    worksheet.write(lno, cno, column)
    cno = cno + 1

def closeExcelSheet(workbook, outputFileName):
  """ Saves the in-memory WorkBook object into the specified file """
  workbook.save(outputFileName)

def getDefaultOutputFileName(inputFileName):
  """ Returns the name of the default output file based on the value
      of the input file. The default output file is always created in
      the current working directory. This can be overriden using the
      -o or --output option to explicitly specify an output file """
  baseName = os.path.basename(inputFileName)
  rootName = os.path.splitext(baseName)[0]
  return string.join([rootName, "xls"], '.')

def renameOutputFile(outputFileName, fno):
  """ Renames the output file name by appending the current file number
      to it """
  dirName, baseName = os.path.split(outputFileName)
  rootName, extName = os.path.splitext(baseName)
  backupFileBaseName = string.join([string.join([rootName, str(fno)], '-'), extName], '')
  backupFileName = os.path.join(dirName, backupFileBaseName)
  try:
    os.rename(outputFileName, backupFileName)
  except OSError:
    print "Error renaming output file:", outputFileName, "to", backupFileName, "...aborting"
    sys.exit(-1)

def validateOpts(opts):
  """ Returns option values specified, or the default if none """
  titlePresent = False
  linesPerFile = -1
  outputFileName = ""
  sepChar = ","
  for option, argval in opts:
    if (option in ("-t", "--title")):
      titlePresent = True
    if (option in ("-l", "--lines")):
      linesPerFile = int(argval)
    if (option in ("-s", "--sep")):
      sepChar = argval
    if (option in ("-o", "--output")):
      outputFileName = argval
    if (option in ("-h", "--help")):
      usage()
  return titlePresent, linesPerFile, sepChar, outputFileName

def main():
  """ This is how we are called """
  try:
    opts,args = getopt.getopt(sys.argv[1:], "tl:s:o:h", ["title", "lines=", "sep=", "output=", "help"])
  except getopt.GetoptError:
    usage()
  if (len(args) != 1):
    usage()
  inputFileName = args[0]
  try:
    inputFile = open(inputFileName, 'r')
  except IOError:
    print "File not found:", inputFileName, "...aborting"
    sys.exit(-1)
  titlePresent, linesPerFile, sepChar, outputFileName = validateOpts(opts)
  if (outputFileName == ""):
    outputFileName = getDefaultOutputFileName(inputFileName)
  workbook, worksheet = openExcelSheet(outputFileName)
  fno = 0
  lno = 0
  titleCols = []
  reader = csv.reader(inputFile, delimiter=sepChar)
  for line in reader:
    if (lno == 0 and titlePresent):
      if (len(titleCols) == 0):
        titleCols = line
      writeExcelHeader(worksheet, titleCols)
    else:
      writeExcelRow(worksheet, lno, line)
    lno = lno + 1
    if (linesPerFile != -1 and lno >= linesPerFile):
      closeExcelSheet(workbook, outputFileName)
      renameOutputFile(outputFileName, fno)
      fno = fno + 1
      lno = 0
      workbook, worksheet = openExcelSheet(outputFileName)
  inputFile.close()
  closeExcelSheet(workbook, outputFileName)
  if (fno > 0):
    renameOutputFile(outputFileName, fno)

if __name__ == "__main__":
  main()

如何使用Shell脚本在Linux中从Excel工作表中读取数据？

2 个答案: