Question

我知道这是一个语法错误，但我不知道我做了什么是错的。错误是

解析错误：语法错误，意外T_CONSTANT_ENCAPSED_STRING，期待T_STRING或T_VARIABLE或第8行的'{'或'$'

，代码是

   class Person {
    public $isAlive=true;
    public $firstname;
    public $lastname;
    public $age;
    public function __construct()
    {
    $teacher->"boring"=$firstname;
    $teacher->"12345"=$lastname;
    $teacher->12345=$age;
    $student->"Natalie Euley"=$firstname;
    $student->"Euley"=$lastname;
    $student->19=$age;
    }
    public function greet()
    {
    return "Hello, my name is ".$this->firstname." ".$this->lastname. "Nice to meet you!";
    }
    }
    $student = new Person();
    $teacher = new Person();
    echo $student->greet();
    echo $techer->greet();

我现在明白了。 CodeAcademy有令人困惑的方向。我现在得到了怎么做。谢谢你解释一切！

Answer 1

你应该这样做：

$teacher->"boring" = $firstname;

像这样：

$this->firstname = "boring";

对于你拥有其余代码的方式，你正在寻找的是这样的东西：

public function __construct($firstname, $lastname, $age)
{
    $this->firstname = $firstname;
    $this->lastname  = $lastname;
    $this->age       = $age;
}

$teacher = new Person("John", "Smith", 45);

Answer 2

您的语法不正确。

$this->firstname = "boring";
$this->lastname = "12345";

如果您要将这些值分配给您所在的班级，我们会使用“this”。

它是

$object->variable = value;

Answer 3

这些是错误的

$teacher->"boring"=$firstname;
$teacher->"12345"=$lastname;
$teacher->12345=$age;
$student->"Natalie Euley"=$firstname;
$student->"Euley"=$lastname;
$student->19=$age;

应该是

$teacher->firstname = "boring";
$teacher->lastname = "12345";
$teacher->age = 12345;
$student->firstname = "Natalie Euley";
$student->lastname ="Euley";
$student->age = 19;

点击这里

http://www.php.net/manual/en/language.oop5.php

Answer 4

这样的东西：

$student->"Natalie Euley"=$firstname;

无效。可能你的意思是

$student->firstname = "Natalie Euley";

您不能使用"string"作为对象键引用。但你可以使用：

$student->{"Natalie Euley"} = $firstname
          ^--             ^--note the brackets

然而，这仍然是倒退。这样的作业应该key => $value，而你正在做$value => key，这是低音的。

Answer 5

构造函数方法中存在语法错误。例如，以下行不正确的PHP代码：

$student->"Natalie Euley"=$firstname;

我建议您阅读http://www.php.net/manual/en/language.oop5.php

上的官方文档

根据您改进的代码示例工作正常：

class Person {
    public $isAlive = true;
    public $firstName;
    public $lastName;
    public $age;

    public function __construct($firstName, $lastName, $age) {
        $this->firstName = $firstName;
        $this->lastName = $lastName;
        $this->age = $age;
    }

    public function greet() {
        return 'Hello, my name is ' . $this->firstName . ' ' . $this->lastName .
            ' and I\'m '. $this->age . ' years old. Nice to meet you!';
    }
}

$student = new Person('Max', 'Kid', 19);
$teacher = new Person('Albert', 'Einstein', 60);
echo $student->greet() . "\n";
echo $teacher->greet();

我不明白为什么我得到这个错误

5 个答案: