Question

以下程序对包含Map<Integer, List<Integer>>字段的类进行编组和解组。

解组后，地图中的列表包含字符串而非整数。

是否有一种简单的方法可以确保列表将填充整数而不是解组时的字符串？

import java.io.StringReader;
import java.io.StringWriter;
import java.util.Arrays;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlRootElement;
import org.eclipse.persistence.jaxb.JAXBContextFactory;
import org.eclipse.persistence.jaxb.MarshallerProperties;
import org.eclipse.persistence.oxm.MediaType;

public class MapApp {

    @XmlRootElement
    public static class Publication {

        private String name;

        private Map<Integer, List<Integer>> yearToIssues;

        public void setName(String name) {
            this.name = name;
        }

        public String getName() {
            return name;
        }

        public void setYearToIssues(Map<Integer, List<Integer>> yearToIssues) {
            this.yearToIssues = yearToIssues;
        }

        public Map<Integer, List<Integer>> getYearToIssues() {
            return yearToIssues;
        }

    }

    public static void main(String[] args) throws JAXBException {
        Publication publication = new Publication();
        publication.setName("JAXB miracles");
        Map<Integer, List<Integer>> yearToIssues = new HashMap<>();
        yearToIssues.put(2013, Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12));
        yearToIssues.put(2014, Arrays.asList(1, 2));
        publication.setYearToIssues(yearToIssues);
        String marshalled = marshal(publication);
        Publication uPublication = unmarshal(Publication.class, marshalled);
        List<Integer> issues = uPublication.getYearToIssues().get(2013);
        if (((Object) issues.get(0)) instanceof String) {
            System.out.println("issue is instance of String!");
        }

    }

    static String marshal(Object toMarshal) throws JAXBException {
        JAXBContext jc = JAXBContextFactory.createContext(new Class[] {toMarshal.getClass()}, null);
        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty(MarshallerProperties.MEDIA_TYPE, MediaType.APPLICATION_XML);
        StringWriter sw = new StringWriter();
        marshaller.marshal(toMarshal, sw);
        System.out.println(sw);
        return sw.toString();
    }

    static <T> T unmarshal(Class<T> entityClass, String str) throws JAXBException {
        JAXBContext jc = JAXBContextFactory.createContext(new Class[] {entityClass}, null);
        Unmarshaller unmarshaller = jc.createUnmarshaller();
        unmarshaller.setProperty(MarshallerProperties.MEDIA_TYPE, MediaType.APPLICATION_XML);
        return (T) unmarshaller.unmarshal(new StringReader(str));
    }

}

Answer 1

您需要为XmlAdapter编写Map<Integer, List<Integer>>来正确处理此用例。

http://blog.bdoughan.com/2010/07/xmladapter-jaxbs-secret-weapon.html

如何编组/解组Map <integer，list <integer =“”>＆gt;？</integer，>

1 个答案: