Question

我正在尝试在Match boolean模式中查找下一个和上一个ID。这就是我的尝试：

SELECT id
FROM songs 
WHERE MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE)
ORDER BY MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE) DESC

结果：

SQL小提琴（结果）：http://sqlfiddle.com/#!9/d369d/7

然后在id 32138之后找到下一个ID：

SELECT id
FROM songs 
WHERE 
    id < '32138'
  AND 
    MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE)
ORDER BY MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE) DESC LIMIT 1

根据上述结果，下一个id应为32221，但结果为空。

SQL小提琴（下一个ID）：http://sqlfiddle.com/#!9/d369d/9

请帮忙吗？

Answer 1

您正在where子句中比较* id * s，并且您正在寻找低于最低id的{{1}}值。您想要与id结果进行比较：

match

编辑：

当然，多首歌曲可以具有相同的匹配值。考虑到这一点：

SELECT s.id
FROM songs s cross join
     (select MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE) as matchresult
      from songs s
      where id = 32138
     ) s32138
WHERE MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE) < s32138.matchresult and
      MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE)
ORDER BY MATCH (artist) AGAINST ('alpha delta beta' IN BOOLEAN MODE) DESC
LIMIT 1;

Mysql在匹配布尔模式下选择next和previous ID

1 个答案: