SearchDisplayController上的空单元格

Question

我正在尝试将SearchDisplayController实现为tableView。

当我创建我的tableview时，一切都可以。 我有一个带有UitableViewController委托的UiViewController。

这是我的.h

    #import <UIKit/UIKit.h>
#import "AppDelegate.h"
@interface getClientsViewController : UIViewController <UITableViewDelegate,UITableViewDataSource> {
    IBOutlet UIView *vistaClientes;
    IBOutlet UIView *menu;
    IBOutlet UITableView *tablita;
}

@property(nonatomic, retain) AppDelegate *app;
@property(nonatomic, retain) NSMutableDictionary *clientList;
@property(nonatomic, retain) IBOutlet UIView *vistaClientes;
@property(nonatomic, retain) IBOutlet UIView *menu;
@property(nonatomic, retain) NSString *menuPos;
@property(nonatomic, retain) IBOutlet UITableView *tablita;

-(IBAction)showMenu:(id)sender;
@end

这是我的.m

#import "getClientsViewController.h"
#import "checkInternet.h"
#import "AccessLogin.h"
#import "ClientesCell.h"
#import "menuGlobalViewController.h"
#import "getOrdenesViewController.h"
#import "InterfaceGLobal.h"

@interface getClientsViewController ()

@end
@implementation getClientsViewController {
    NSArray *recipes;
    NSArray *searchResults;
}
@synthesize app,clientList,vistaClientes,menuPos,menu,tablita;


- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope
{

    NSArray *cliente = [NSArray arrayWithArray:[clientList objectForKey:@"clients"]];

    NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"nickname contains[c] %@ OR clientNumber contains[c] %@",searchText, searchText];
    searchResults = [cliente filteredArrayUsingPredicate:resultPredicate];
}

-(BOOL)searchDisplayController:(UISearchDisplayController *)controller shouldReloadTableForSearchString:(NSString *)searchString
{
    [self filterContentForSearchText:searchString
                               scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                      objectAtIndex:[self.searchDisplayController.searchBar
                                                     selectedScopeButtonIndex]]];

    return YES;
}

#pragma mark - Table view data source

-(NSInteger)numberOfSectionsInTableView:(UITableView *)tableView {
    return 1;
}

-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
    if (tableView == self.searchDisplayController.searchResultsTableView) {

        return [searchResults count];

    } else {
    return [[clientList objectForKey:@"clients"] count];
    }
}

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {


    static NSString *CellIdentifier = @"ClienteCelda";
    ClientesCell *cell = (ClientesCell *)[self.tablita dequeueReusableCellWithIdentifier:CellIdentifier];

        if (cell == nil) {
            NSLog(@"Im in");
            cell = [[ClientesCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier];
        }




    NSArray *cliente = [NSArray array];
    if (tableView == self.searchDisplayController.searchResultsTableView) {
       cliente = [NSArray arrayWithArray:searchResults];
    } else {
        cliente = [NSArray arrayWithArray:[clientList objectForKey:@"clients"]];
    }


    [cell.Direccion setText:[[cliente objectAtIndex:indexPath.row] objectForKey:@"address1"]];

    [cell.nombreCliente setText:[[cliente objectAtIndex:indexPath.row] objectForKey:@"name"]];
    [cell.nombreCorto setText:[[cliente objectAtIndex:indexPath.row] objectForKey:@"nickname"]];
    [cell.imagen setImage:[UIImage imageNamed:@"avatar.png"]];

    NSLog(@"cellda: %@",[[cliente objectAtIndex:indexPath.row] objectForKey:@"address1"]);

    return cell;
}

我有一些方法，只是为了使代码更加可见。

当视图加载时，正确显示结果，但是当我键入一些搜索时，返回默认样式的空单元格。

我知道，当我搜索时，if（cell == nil）为true，但未正确加载样式。

有人可以帮帮我吗？

以下两个屏幕截图将有助于解释：