Question

编写程序以不断要求用户输入数字，直到用户输入大于100的数字为止。然后打印最后一次输入前的数字的平均值。例如，如果用户输入12,23,9,15,155，则输入终止（因为155> 100）并且您的程序打印平均值12,23,9,15，即14.75。

这是我迄今为止所做的，似乎无法让它正常工作

def average():
 inputnum = 0
 numlist = []
while inputnum <=100:
 inputnum = input("Please input a number: ")
 inputnum = float(inputnum)
 numlist.append(inputnum)
average = sum(numlist)/len(numlist)
print(average)

Answer 1

你的程序对我来说很好，但缩进是错误的。它必须是这样的：

def average():
    inputnum = 0
    numlist = []
    while inputnum <=100:
        inputnum = input("Please input a number: ")
        inputnum = float(inputnum)
        numlist.append(inputnum)
    average = sum(numlist)/len(numlist)
    print(average)

average() # finally call the function

要排除输入的数字大于100，请执行以下操作：

def average():
    inputnum = 0
    numlist = []
    while inputnum <=100:
        inputnum = input("Please input a number: ")
        inputnum = float(inputnum)
        numlist.append(inputnum) if inputnum <=100 else None
    average = sum(numlist)/len(numlist)
    print(average)

average() # finally call the function

对于Jython：

def average():
    inputnum = 0
    numlist = []
    while inputnum <=100:
        inputnum = input("Please input a number: ")
        inputnum = float(inputnum)
        if inputnum <= 100:
            numlist.append(inputnum)
    average = sum(numlist)/len(numlist)
    print(average)

average() # finally call the function

Python中的平均函数

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