Question

我的应用程序中包含许多其他NSDictionary的{{1}}。如果我打印出这本字典，它的内容如下：

NSDictionary

我的应用程序以{：1>的名称访问oxip = { created = "2014-02-10 14:42:59"; lastMsgId = ""; requestTime = "1.6434"; response = { code = 001; debug = ""; message = success; request = getHierarchyByMarketType; text = "\n"; williamhill = { class = { id = 1; maxRepDate = "2014-02-10"; maxRepTime = "07:31:48"; name = "UK Football"; text = "\n"; type = ( { id = 2; lastUpdateDate = "2013-12-26"; lastUpdateTime = "13:32:54"; market = ( { betTillDate = "2014-02-15"; betTillTime = "15:00:00"; date = "2014-02-15"; id = 140780553; lastUpdateDate = "2014-02-10"; lastUpdateTime = "14:09:13"; name = "Queen of the South v Dundee - Match Betting"; participant = ( { handicap = ""; id = 496658381; lastUpdateDate = "2014-02-10"; lastUpdateTime = "14:09:13"; name = Dundee; odds = "11/8"; oddsDecimal = "2.38"; text = "\n\n\n\n\n\n"; }, { handicap = ""; id = 496658380; lastUpdateDate = "2014-02-10"; lastUpdateTime = "14:09:13"; name = Draw; odds = "5/2"; oddsDecimal = "3.50"; text = "\n"; }, { handicap = ""; id = 496658379; lastUpdateDate = "2014-02-10"; lastUpdateTime = "14:09:13"; name = "Queen of the South"; odds = "11/8"; oddsDecimal = "2.38"; text = "\n"; } ); text = "\n"; time = "15:00:00"; }的最佳方式是什么？

name =“南方女王v邓迪 - 比赛投注”

无需遍历每个单独的字典并找到其对象的对象？

Answer 1

您可以使用valueForKeyPath。它接受一个由点分隔的路径。例如：

NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:@"https://dl.dropboxusercontent.com/u/1365846/21680479.json"]]
                                                     options:0
                                                       error:nil];
NSLog(@"%@", [dict valueForKeyPath:@"response.williamhill.class.type.market.name"]);

这取决于字典的表示。如果williamhill部分正在发生变化，那么它当然不起作用。

Answer 2

无法遍历地图数据类型（在本例中为NSDictionary）而无法遍历它。想想这个问题的简化版本：你有一个包含N个元素的链表，你希望到达第N个元素。因为这是一个链表，所以你必须遍历所有其他N-1个节点才能获得最后一个参考。

NSDictionary是基于散列的数据类型，其中存储了键和值。在您描述的情况下，您没有引用嵌套对象（NSDictionary本身），因此您还必须遍历包含它的所有字典。

希望这有助于指明你正确的方向。

从另一个NSDictionary中提取NSDictionary

2 个答案: