Question

我在java中使用此代码来验证银行帐号，我正在尝试将其转换为objective-c但我认为我的代码无法正常工作，这里是代码：

JAVA 1：

public boolean isValid(final String accountCnumber,
        final ConstraintValidatorContext constraintValidatorContext) {
    if ((accountCnumber == null) && optional) {
        return true;
    }
    else {
        if (accountCnumber == null) {
            return false;
        }
        else {
            boolean result;
            if (accountCnumber.length() == 12) {
                final String auxAccountNumber = accountCnumber.substring(3,5)+ accountCnumber.substring(0, 3) + accountCnumber.substring(5, 12);
                Integer principalCounter = 0;
                Integer counter = 0;
                for (int i = 0; i < auxAccountNumber.length() - 1; i++) {

                    principalCounter = checkData(auxAccountNumber,
                            principalCounter, i);

                }

                final Integer cont = (principalCounter + 10) * 10;
                counter = cont - principalCounter;
                final String lastAux = counter.toString().substring(counter.toString().length() - 1);
                final String last = accountCnumber.substring(11);

                result = lastAux.equals(last);
            }
            else {
                result = false;
            }
            return result;
        }
    }
}

我的目标-c尝试1 :(我认为错误是从.subString传递到NSRange）

-(BOOL)accountValidation: (NSString *)accountCnumber
{

    if ([accountCnumber isEqualToString:@""] || accountCnumber == nil) {
        return false;
    }else{
        Boolean result;
        if (accountCnumber.length == 12) {

            /*
             000200041901
            */

            NSString *auxAccountNumber = @"";

            NSRange range1 = NSMakeRange(3, 2); //20
            NSRange range2 = NSMakeRange(0, 3); //000
            NSRange range3 = NSMakeRange(5, 7); //0041901

            NSString *subString1 = [accountCnumber substringWithRange:range1];
            NSString *subString2 = [accountCnumber substringWithRange:range2];
            NSString *subString3 = [accountCnumber substringWithRange:range3];

            NSLog(@"subString1  20=%@",subString1);
            NSLog(@"subString2  000=%@",subString2);
            NSLog(@"subString3 0041901=%@",subString3);

            auxAccountNumber = [NSString stringWithFormat:@"%@%@%@",subString1,subString2,subString3];

            NSLog(@"auxAccountNumber = %@",auxAccountNumber);

            int principalCounter = 0;
            int counter = 0;

            for (int i = 0; i < auxAccountNumber.length - 1; i++) {

                //principalCounter = checkData(auxAccountNumber,principalCounter, i);

                principalCounter = [self checkData:auxAccountNumber p:principalCounter counter:i];

            }

            int cont = (principalCounter + 10) * 10;
            counter = cont - principalCounter;

            NSString *strFromInt = [NSString stringWithFormat:@"%d",counter];

            NSString *lastAux = [strFromInt substringFromIndex:[strFromInt length]-1];

            NSString *last = [accountCnumber substringFromIndex:11];

            //result = lastAux.equals(last);

            if ([lastAux isEqualToString:last]) {
                result = true;
            }else{
                result = false;
            }

        }
        else {
            result = false;
        }
        return result;
    }
}

JAVA 2：

private Integer checkData(final String auxAccountNumber, final Integer pCounter, final int i) {
    Integer principalCounter = pCounter;
    Integer counter = 0;
    Integer aux;
    if (i % 2 == 0) {
        counter = Integer.parseInt(Character.toString(auxAccountNumber.charAt(i))) * 2;
        if (counter >= 10) {
            counter = counter - 9;
        }
        principalCounter = principalCounter + counter;
    }
    else {
        aux = Integer.parseInt(Character.toString(auxAccountNumber.charAt(i)));
        principalCounter = principalCounter + aux;
    }
    return principalCounter;
}

我的目标-c尝试：

-(int)checkData:(NSString *)auxAccountNumber p:(int)pCounter counter:(int)i
{
    int principalCounter = pCounter;
    int counter = 0;
    int aux=0;
    if (i % 2 == 0) {
        NSString *s = auxAccountNumber;
        const char *c = [s UTF8String];

        counter = c[i] * 2;

        if (counter >= 10) {
            counter = counter - 9;
        }
        principalCounter = principalCounter + counter;

    }else {
        NSString *s = auxAccountNumber;
        const char *c = [s UTF8String];
        counter = c[i] * 2;
        principalCounter = principalCounter + aux;
    }
    return principalCounter;

}

很抱歉很长的帖子，但我真的需要这个：）

编辑我有这些有效的银行帐号用于测试@“000200041901”和@“001200144174”方法“accountValidation”的结果必须返回true，但问题是它总是返回false。

Answer 1

以下是重写的第二种方法的示例，其中更好地命名和消除了冗余：

- (int)checkDataAuxAccountNumber:(NSString *)auxAccountNumber pCounter:(int)pCounter digitIndex:(int)digitIndex {
    NSString *digitString = [auxAccountNumber substringWithRange:NSMakeRange(digitIndex, 1)];
    int digit = [digitString intValue];

    if (digitIndex % 2 == 0) {
        digit *= 2;
        if (digit >= 10) {
            digit -= 9;
        }
    }

    return pCounter + digit;
}

以类似的方式转换第一种方法然后为Java和Objective-C代码创建一些测试代码。

将java函数（验证银行帐号）转换为目标c

1 个答案: