JAVA中的GPG解密

Question

public static void doDecrypt(String source,String dest ){

    Runtime rt = Runtime.getRuntime();
    GPGDecrypt rte = new GPGDecrypt();
    Process proc;
    StreamWrapper error, output = null ;

    try {       

        proc = rt.exec("gpg --output "+dstfile +" --batch --passphrase "+ResourcePropertyManager.get("Passphrase")+ " --decrypt "+srcfile);

        System.out.println("After Passing");

        error = rte.getStreamWrapper(proc.getErrorStream(), "ERROR");

        output = rte.getStreamWrapper(proc.getInputStream(), "OUTPUT");

        int exitVal = 0;

        error.start();
        output.start();
        error.join(3000);
        output.join(3000);          
        exitVal = proc.waitFor();

        System.out.println("Output: " + output.message + "\nError: "+ error.message);

    } catch (IOException e) {
        System.out.println("IO "+e.getMessage());

        e.printStackTrace();
    } catch (InterruptedException e) {
        System.out.println("IEX"+e.getMessage());
        // TODO Auto-generated catch block
        e.printStackTrace();
    }   finally{
        rt = null;
        rte = null;
        proc = null;
        error = null;
        output = null;
    }
}

在通过上面的代码动态传递值时，不会生成输出文件。

我在Windows中运行它。