Question

我有一个自定义数据类型的列表，简化示例（myMovies）：

public class Movie
{
    public Int32 TVIndex;
    public string MovieName;
    public string MovieRating;
    public string MovieRuntime;
    public List<Actor> MovieActors;
    public List<MovieArt> MovieImages;
}



public class Actor
{
    public string ActorName;
    public string ActorRole;
}

public class MovieArt
{
    public string ImagePath;
}


List<Movie> myMovies = new List<Movie>();

现在我尝试从myMovies删除所有重复项，但忽略TVIndex。

我试过看

List<Movie> myDistinctMovies = myMovies.Distinct().ToList();

但无法弄清楚如何忽略TvIndex。这可能吗？

Answer 1

基于@Grundy的回答，包括实施：

public class MovieEqualityComparer : IEqualityComparer<Movie>
{

    public bool Equals(Movie x, Movie y)
    {
        if ( x == null )
            return y == null;

        if ( y == null )
            return x == null;

        if ( object.ReferenceEquals(x, y) )
            return true;

        if ( !string.Equals(x.MovieName, y.MovieName) )
            return false;

        if ( !string.Equals(x.MovieRating, y.MovieRating) )
            return false;

        if ( !string.Equals(x.MovieRuntime, y.MovieRuntime) )
            return false;

        if ( !Enumerable.SequenceEqual(x.MovieActors, y.MovieActors) )
            return false;

        if ( !Enumerable.SequenceEqual(x.MovieImages, y.MovieImages) )
            return false;

        return true;
    }

    public int GetHashCode(Movie obj)
    {
        if ( obj == null )
            throw new ArgumentNullException();

        unchecked
        {
            int hash = 17;
            hash     = hash * 31 + ((obj.MovieName    == null) ? 0 : obj.MovieName.GetHashCode());
            hash     = hash * 31 + ((obj.MovieRating  == null) ? 0 : obj.MovieRating.GetHashCode());
            hash     = hash * 31 + ((obj.MovieRuntime == null) ? 0 : obj.MovieRuntime.GetHashCode());

            if ( obj.MovieActors != null )
            {
                foreach ( var actor in obj.MovieActors )
                    hash = hash * 31 + ((actor == null) ? 0 : actor.GetHashCode());
            }

            if ( obj.MovieImages != null )
            {
                foreach ( var image in obj.MovieImages )
                    hash = hash * 31 + ((image == null) ? 0 : image.GetHashCode());
            }

            return hash;
        }
    }
}

用法是一样的：

List<Movie> myMovies = new List<Movie>
    {
        // ...
    }; 

List<Movie> myDistinctMovies = myMovies.Distinct(new MovieEqualityComparer()).ToList();

修改

正如@Tim指出的那样，如果你想通过除引用相等之外的任何东西进行比较，你必须为你的其他自定义类型做一些非常类似的事情。

public class Actor : IEquatable<Actor> { public string ActorName; public string ActorRole; public override bool Equals(object obj) { return this.Equals(obj as Actor); } public bool Equals(Actor other) { if ( other == null ) return false; if ( object.ReferenceEquals(this, other) ) return true; if ( !string.Equals(this.ActorName, other.ActorName) ) return false; if ( !string.Equals(this.ActorRole, other.ActorRole) ) return false; return true; } public override int GetHashCode() { unchecked { int hash = 17; hash = hash * 31 + ((ActorName == null) ? 0 : ActorName.GetHashCode()); hash = hash * 31 + ((ActorRole == null) ? 0 : ActorRole.GetHashCode()); return hash; } } } public class MovieArt : IEquatable<MovieArt> { public string ImagePath; public override bool Equals(object obj) { return this.Equals(obj as MovieArt); } public bool Equals(MovieArt other) { if ( other == null ) return false; if ( object.ReferenceEquals(this, other) ) return true; if ( !string.Equals(this.ImagePath, other.ImagePath) ) return false; return true; } public override int GetHashCode() { unchecked { int hash = 17; hash = hash * 31 + ((ImagePath == null) ? 0 : ImagePath.GetHashCode()); return hash; } } }

Answer 2

您可以使用Distinct with EqualityComparer这样的内容

public class MoviesEqualityComparer : IEqualityComparer<Movie>
{
    public bool Equals(Movie x, Movie y)
    {
        return ..../* check all needed fields */

    }

    public int GetHashCode(Movie obj)
    {
        return .... /* get hashcode for movie objec*/
    }
}

并像

一样使用它

List<Movie> myDistinctMovies = myMovies.Distinct(new MoviesEqualityComparer()).ToList();

Answer 3

您可以使用LINQ查询...

List<Movie> myDistinctMovies  = (myMovies .GroupBy(p =>p.MovieName,
                                                   p =>p.MovieRating,p=>p.MovieRuntime)
                                          .Select(g => g.First())
                                          .ToList());

谢谢..

选择不同于List <t>忽略一个元素</t>

3 个答案: