Question

我已经写了一个宏来从一张纸到另一张纸上获取一些excel数据，以便我可以根据条件轻松使用数据

Sub page(rowNumber As Integer)

    Dim row_number As Integer
    Dim iterator As Integer
    Dim srch_string As String ' Searching for the string view
    Dim IdMethod As String
    Dim UIValues As String
    Dim Name As String
    Dim SheetName As String
    Dim number As Integer
    Dim result As String

    result = " "
    IdMethod = " "
    UIValues = " "
    row_number = rowNumber
    iterator = row_number
    Name = ActiveWorkbook.FullName
    srch_string = "onclick"
    number = 3
    SheetName = "page"
    Application.Worksheets(SheetName).Activate
    'while   i= rowNumber
    Do While iterator > 0
        If srch_string = Worksheets(SheetName).Cells(iterator, 5) Then
          Exit Do
        Else
          IdMethod = IdMethod & ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 4)
          UIValues = UIValues & ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
          For Index = 2 To Worksheets("param").UsedRange.Rows.Count
             If ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5) = ActiveWorkbook.Worksheets("param").Cells(Index, 1) Then
                    Do While munber > 0
                        If result <> srch_string Then
                            Exit Do
                        Else
                            result = ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
                            ActiveWorkbook.Worksheets("param").Cells(number, 1) = ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
                            number = number + 1
                            iterator = iterator - 1
                        End If
             End If
             iterator = iterator - 1
    End If
    Loop
    End Sub

但是如果没有阻止，宏表示结束... 我不确定所有的语法但是所有的ifs都被正确放置，因为我知道无法弄清楚出了什么问题

Answer 1

Sub page(rowNumber As Integer)

    Dim row_number As Integer
    Dim iterator As Integer
    Dim srch_string As String ' Searching for the string view
    Dim IdMethod As String
    Dim UIValues As String
    Dim Name As String
    Dim SheetName As String
    Dim number As Integer
    Dim result As String

    result = " "
    IdMethod = " "
    UIValues = " "
    row_number = rowNumber
    iterator = row_number
    Name = ActiveWorkbook.FullName
    srch_string = "onclick"
    number = 3
    SheetName = "page"
    Application.Worksheets(SheetName).Activate
    'while   i= rowNumber
    Do While iterator > 0
        If srch_string = Worksheets(SheetName).Cells(iterator, 5) Then
          Exit Do
        Else
          IdMethod = IdMethod & ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 4)
          UIValues = UIValues & ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
          For Index = 2 To Worksheets("param").UsedRange.Rows.Count
             If ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5) = ActiveWorkbook.Worksheets("param").Cells(Index, 1) Then
                    Do While munber > 0
                        If result <> srch_string Then
                            Exit Do
                        Else
                            result = ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
                            ActiveWorkbook.Worksheets("param").Cells(number, 1) = ActiveWorkbook.Worksheets(SheetName).Cells(iterator, 5)
                            number = number + 1
                            iterator = iterator - 1
                        End If
                   Next '<- Add Next Here (Missing in your code)
             End If
         Next '<- Add Next Here (Missing in your code)
             iterator = iterator - 1
    End If
    Loop
    End Sub

Answer 2

您缺少关闭的下一个索引

    For Index = 2 To Worksheets("param").UsedRange.Rows.Count

修改

正如@simoco和@brain指出的那样，你还需要关闭Do While nunber＆gt; 0与Loop。

Macro说'如果有阻止，则结束'，但所有if块都在那里

2 个答案: