Question

在python中如何找到字符串用单引号括起来

  arr=["string","string'1" ,"'string2'"]

   for i in arr:
      if i //string enclosed in single quotes condition
            print "found"
            print i //which sould print only string2 in this case

Answer 1

最简单的方法是检查它是否以引号开头和结尾：

if i.startswith("'") and i.endswith("'"):
    print "found"

这当然不会告诉你任何其他内容，例如它是否包含匹配的引号，或者确实包含的不仅仅是单引号字符。如果这很重要，那么添加一个检查表明字符串长于一个字符（如果你希望它在引号之间包含某些内容，则大于2）：

if i.startswith("'") and i.endswith("'") and len(i) > 1:
    print "found"

Answer 2

arr=["string","string'1" ,"'string2'"]
for item in arr:
    if len(item) > 1 and item[0] == item[-1] == "'":
        print "found", item

Answer 3

<强>代码：

arr=["'","''","'''","'item","'item'","i'tem'"]
for i in arr:
    if(len(i) > 1):
        if i.startswith("'") and i.endswith("'"):
            print("found")
            print(i)

<强>输出：

found
''
found
'''
found
'item'

如果第一个和最后一个字母相等且等于'，则字符串以引号开头和结尾。忽略长度为1的字符串，因为它们可能是单引号，假设这可能会导致系统出现问题。

Answer 4

arr=["string","string'1" ,"'string2'"]
for each in arr:
  if each[0] =="'" and each[-1] =="'":
     print 'found'
     print each

Python查找用单引号括起来的字符串

4 个答案: