表类

ClassName  Student (XML)
A
B
C

以下是EACH行中的XML结构

<Students>
 <Class>A</Class>
 <Student>
  <Name>John</Name>
  <Hobbies>Music,Reading,Baseball</Hobbies>
 </Student>
 <Student>
  <Name>David</Name>
  <Hobbies></Hobbies>
 </Student>
 <Student>
  <Name>Sofiya</Name>
  <Hobbies>Surfing,Basketball</Hobbies>
 </Student>
</Students>

在这里，我想通过用';'替换'，'来更新爱好节点。我想在每一行中做所有行和所有业余爱好。

我的查询应该是什么来实现这一目标？我尝试了这个，但不是替换'，'而是用';'替换整个文本

 declare @i int

 select top 1 @i = count(*) 
 from @table as o
     outer apply o.data.nodes('
            Students/
            Student[
                 Hobbies[contains(., ",")]]/Hobbies/text()                             
     ') as T(C) 
 order by count(*)
 print @i
 while @i > 0
 begin
     update @table set
         data.modify('
             replace value of 
             (
                  Students/
            Student[
                 Hobbies[contains(., ",")]]/Hobbies/text()     
             )[sql:variable("@i")][1]
             with ";"
        ') 

     set @i = @i - 1
 end;

Answer 1

这对你有用吗</ p>

declare @table table (classname varchar(10), students xml)
insert into @table values
('A','<Students>
 <Class>A</Class>
 <StudentA>
    <Name>John</Name>
    <Hobbies>Music,Reading,Baseball</Hobbies>
 </StudentA>
 <StudentB>
    <Name>David</Name>
    <Hobbies></Hobbies>
 </StudentB>
 <StudentC>
    <Name>Sofiya</Name>
    <Hobbies>Surfing,Basketball</Hobbies>
 </StudentC>
</Students>');

SELECT * from @table
update @table
set students=convert(xml,replace(convert(varchar(max),students),',',';'))

select * from @table;

假设不，出现在爱好以外的任何地方

更新多个节点在XML属性中的所有出现

表类

1 个答案: