我的问题不是关于xpath语法,它与围绕xpath的java API有关。请考虑以下xml:
<wrapper>
<metadata>
<somefield>somevalue</somefield>
<anotherfield>othervalue</anotherfield>
</metadata>
<data>
<some>
<unique>
<xml>
<structure>stuff</structure>
</xml>
</unique>
</some>
</data>
</wrapper>
我可以使用以下代码轻松获取使用xpath的元数据字段:
XPath xp = XPathFactory.newInstance().newXPath();
Node node = (Node) xp.evaluate("/wrapper/metadata/somefield", xmlDoc, XPathConstants.NODE);
String somefield = node.getFirstChild().getNodeValue();
我正在努力学习如何从<some>
标记开始获取表示xml的子树的字符串。换句话说,我编写什么代码来获取一个字符串,打印出来时会打印出以下内容? xpath查询将是&#34; / wrapper / data / some&#34;,但我不知道如何正确使用xpath api。
<some>
<unique>
<xml>
<structure>stuff</structure>
</xml>
</unique>
</some>
答案 0 :(得分:5)
您只需要使用Node
将XPathExpression
从String
转换为Transformer
,就像将文档写入文件一样,这是一个完整的例子:
public static void main(String[] args) throws Exception {
final String xml = "<wrapper>\n"
+ " <metadata>\n"
+ " <somefield>somevalue</somefield>\n"
+ " <anotherfield>othervalue</anotherfield>\n"
+ " </metadata>\n"
+ " <data>\n"
+ " <some>\n"
+ " <unique>\n"
+ " <xml>\n"
+ " <structure>stuff</structure>\n"
+ " </xml>\n"
+ " </unique>\n"
+ " </some>\n"
+ " </data>\n"
+ "</wrapper>";
final Document doc = DocumentBuilderFactory.newInstance().newDocumentBuilder().parse(new ByteArrayInputStream(xml.getBytes(Charsets.UTF_8)));
final XPathExpression xpath = XPathFactory.newInstance().newXPath().compile("//some");
final Node node = (Node) xpath.evaluate(doc, XPathConstants.NODE);
StringWriter sw = new StringWriter();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
transformer.setOutputProperty(OutputKeys.METHOD, "xml");
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
transformer.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
transformer.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
transformer.transform(new DOMSource(node), new StreamResult(sw));
System.out.println(sw.toString());
}