Question

请帮我通过PHP代码将报告参数传递给“Reportica报告”。

这是我尝试过的方法：

PHP代码：

require_once('../reportico/reportico.php'); 

$q = new reportico();

$q->initial_project = "loansys";
$q->initial_project_password = "k013";
$q->initial_report = "loansys.xml";
$q->initial_output_format = "HTML";
$q->embedded_report = true;

$q->allow_debug = true;
$q->forward_url_get_parameters = "";
$q->external_param1 = 1; 
$q->execute($q->get_execute_mode(), true);

报告查询：

SELECT l_number,due_number,due_date,amount,capital,interest
FROM  loan_due
WHERE l_number = {external_param1}

错误讯息：

错误：连接中的错误（1064）：您的SQL语法中有错误;检查与MySQL服务器版本对应的手册，以便在第3行附近的'}）'附近使用正确的语法

Answer 1

我的剧本：

        require_once('../reportico/reportico.php'); 
        $q = new reportico();
        $q->initial_project = "xxxx";
        $q->initial_project_password = "xxxx";
        $q->initial_report = "xxxx.xml";
        $q->initial_execute_mode = "MENU";
        $q->access_mode = "SInGLEPROJECT";
        $q->embedded_report = true;
        $q->user_parameters["lnumber"] =  $_POST['cmblnumber'];
        $q->execute();

我的reportico查询：

select 
    l_number, due_number, due_date, amount, capital, interest
from 
    loan_due
where
    l_number = "{USER_PARAM,lnumber}"
limit 
    0, 30

Reportico - 报告参数传递

1 个答案: