Question

我只是输了。如果我删除admin重置部分，同时当我使用admin reset部分运行程序并输入“reset”作为参数时，我的代码运行良好。管理员重置部分重置它需要重置的内容。简而言之，它们分别在工作但它们在一起它不会运行，因为当我单击构建和运行按钮（在codeblocks中）它将显示控制台一段时间然后Windows将弹出“program.exe已停止工作”对话框。怎么了？在这里，我只是粘贴第一部分。

///admin reset
if(strcmp(argv[1], "reset")==0){
    printf("Hello admin. You now have the power to reset the program.\n Press 'y' to proceed or press any key yo cancel: ");
    fflush(stdin);
    scanf("%c", &choice);
    if (choice == 'y'){
        remove("db.txt");
        remove("phonebook.txt");
        printf("Program will now exit. Thank You. Good day.\n");
    }
}
///retrieve data
    db = fopen("db.txt", "r");

    if (db==NULL){
    printf("\a");
    db = NULL;
    } else {
    ReadLine(db, savedu, sizeof(char[16]));
    ReadLine(db, savedp, sizeof(char[16]));
    fscanf(db, "%d" , &cc);
    pb = (Myphonebooktype*)malloc(cc*sizeof(Myphonebooktype));
    addcounter = cc;


    for(i = 0; i<cc ; i++) {
        fscanf(db, "%d" , &pb[i].num);
        ReadLine(db, pb[i].name, sizeof pb[i].name);
        ReadLine(db, pb[i].address, sizeof pb[i].address);
        ReadLine(db, pb[i].cellphone, sizeof pb[i].cellphone);
        ReadLine(db, pb[i].email, sizeof pb[i].email);
        }
    }

///register and login
if(db==NULL){
    while(1){
        printf("Username and password should not exceed 15 charcaters\nRegister/Login (press enter to exit)\nUsername: ");
        gets(username);

        if (strcmp(username, "") == 0) {
            option = 'X';
            break;
        }

        if(strlen(username)>=16){
            printf("\a");
            printf("username should not exceed 15 characters.\n");
            continue;
        }

        printf("Password: ");
        gets(password);

        if (strcmp(password, "") == 0) {
            option = 'X';
            break;
        }
        if(strlen(password)>=16){
            printf("\a");
            printf("password should not exceed 15 characters\n");
            continue;
        }
        break;
    }
} else {...

Answer 1

我很确定通过一些“调试”，您将能够确定故障代码所在的位置。

查看codeblocks debugger how to

或者，您可以使用具有强大调试功能的Visual Studio。

Answer 2

应为if（argc == 2＆amp;＆amp; strcmp（argv [1]，“reset”）== 0）

插入命令行，程序不会运行

2 个答案: