Question

有表格：

 user_id              Date                Status
    1000        2013-04-02 11:46:10.000       IN
    1001        2013-04-02 11:50:08.000       OUT
    1005        2013-04-02 11:46:24.000       IN
    1005        2013-04-02 12:50:04.000       OUT
    1005        2013-04-02 12:50:10.000       OUT
    1045        2013-04-02 14:46:05.000       IN

我想选择 IN 的最短日期和 OUT 的最长日期

Answer 1

试试这个：

select user_id, min(case when status = 'IN' then Date end) as mindate, 
max(case when status = 'OUT' then Date end) as maxdate, status
from tbl
group by user_id, Status

演示：http://sqlfiddle.com/#!3/9430e/6

另一种方法：

select a.user_id, mindate, maxdate
from 
(
    select user_id, min(date) as mindate, Status
    from tbl
    where Status = 'IN'
    group by user_id, Status) a
left join 
(
   select user_id, max(date) as maxdate, Status
   from tbl
   where Status = 'OUT'
   group by user_id, Status) b 
on a.user_id = b.user_id

演示：http://sqlfiddle.com/#!3/9430e/14

编辑：要检查最小和最大日期是否在您选择的日期范围内，请使用第二个示例在最后添加条件:(如果我理解正确的话）

select a.user_id, mindate, maxdate
from 
(
select user_id, min(date) as mindate, Status
from tbl
where Status = 'IN'
group by user_id, Status) 
a
left join (
select user_id, max(date) as maxdate, Status
from tbl
where Status = 'OUT'
group by user_id, Status) b on a.user_id = b.user_id
where @yourstart date <= maxdate and @yourenddate >= mindate

检查两个日期是否重叠......

Answer 2

超级简单

SELECT Max(Date) FROM MyTable WHERE Status = 'OUT'
SELECT Min(Date) FROM MyTable WHERE Status = 'IN'

选择

SELECT (SELECT Max(Date) FROM MyTable WHERE Status = 'OUT') AS MaxOut,
       (SELECT Min(Date) FROM MyTable WHERE Status = 'IN') AS MinIn

如何选择最大日期和最小日期

2 个答案: