Question

我是数据库中的新手。我正在尝试创建一些表，但它失败并显示错误“接近'INDEX'：语法错误”。这是我生成表格的代码：

        try {
        using( SqliteCommand cmd = _db.CreateCommand() ) {

            // create words table
            cmd.CommandText = "DROP TABLE words";
            cmd.ExecuteNonQuery();
            cmd.CommandText = 
                "CREATE TABLE IF NOT EXISTS words(" +
                    "word_id INTEGER AUTO_INCREMENT," +
                    "word_eng VARCHAR(128)," +
                    "PRIMARY KEY(word_id)" +
                    ")";
            cmd.ExecuteNonQuery();

            // create word_classes table
            cmd.CommandText = "DROP TABLE word_classes";
            cmd.ExecuteNonQuery();
            cmd.CommandText = 
                "CREATE TABLE IF NOT EXISTS word_classes(" +
                    "word_class_id INTEGER," +
                    "word_class_name VARCHAR(50)," +
                    "PRIMARY KEY(word_class_id)" +
                    ")";
            cmd.ExecuteNonQuery();

            // create meanings table
            cmd.CommandText = "DROP TABLE meanings";
            cmd.ExecuteNonQuery();
            cmd.CommandText = 
                "CREATE TABLE IF NOT EXISTS meanings(" +
                    "meaning_id INTEGER AUTO_INCREMENT," +
                    "meaning VARCHAR(100)," +
                    "word_class_id INTEGER," +
                    "PRIMARY KEY(meaning_id)," +
                    "FOREIGN KEY(word_class_id) REFERENCES word_classes(word_class_id)" + 
                    ")";
            cmd.ExecuteNonQuery();

            // create word_meaning_realationship table
            cmd.CommandText = "DROP TABLE word_meaning_realationship";
            cmd.ExecuteNonQuery();
            cmd.CommandText =
                "CREATE TABLE IF NOT EXISTS word_meaning_realationship(" +
                    "word_id INTEGER," +
                    "meaning_id INTEGER," +
                    "FOREIGN KEY(word_id) REFERENCES words(word_id)" +
                    "FOREIGN KEY(meaning_id) REFERENCES meanings(meaning_id)" +
                    ")";
            cmd.ExecuteNonQuery();

            // create decks table
            cmd.CommandText = "DROP TABLE decks";
            cmd.ExecuteNonQuery();
            cmd.CommandText =
                "CREATE TABLE IF NOT EXISTS decks(" +
                    "deck_id INTEGER AUTO_INCREMENT," +
                    "deck_name VARCHAR(128)," +
                    "deck_version INTEGER," +
                    "PRIMARY KEY(deck_id)" +
                    ")";
            cmd.ExecuteNonQuery();

            // create deck_word_relationship table
            cmd.CommandText = "DROP TABLE deck_word_relationship";
            cmd.ExecuteNonQuery();
            cmd.CommandText =
                "CREATE TABLE IF NOT EXISTS deck_word_relationship(" +
                    "deck_id INTEGER," +
                    "word_id INTEGER," +
                    "FOREIGN KEY(deck_id) REFERENCES decks(deck_id)," +
                    "FOREIGN KEY(word_id) REFERENCES words(word_id)" +
                    ")";
            cmd.ExecuteNonQuery();
        }
    } catch( SqliteException ex ) {
        Debug.LogError( "DBError : " + ex.ToString() );
    }

如果你检查我的其他代码来创建表格，我将非常感激，因为我是数据库和mysql的新手，并且对我的代码不太自信:)）

**更新** 我决定暂不考虑索引。我更新了我的代码，这些代码的错误很小，导致代码无效。但是如果你告诉我如何为我应用索引，我会在申请后将其作为正确答案。谢谢你们的帮助。

Answer 1

您的陈述中有不同的错误：

为外键拼写单词REFERENCES。你总是用双“F”写这个，这是错的。不知道这是不是一个错字。
在创建表meaning时，您错过了NOT来检查表是否存在：这应该是CREATE TABLE IF NOT EXISTS
在创建表deck时，您希望在字段text上创建索引，但此字段不存在。因此，您应该在字段name或其他不同的

修复所有这些错误后，我可以在普通的MySQL数据库上执行所有语句（没有测试你的代码，只是直接在数据库上测试语句）。

Answer 2

首先尝试创建表，然后添加如下所示的索引

cmd.CommandText = @"CREATE TABLE IF NOT EXISTS word(" +
                    "id INTEGER PRIMARY KEY AUTOINCREMENT," +
                    "word VARCHAR(128))";
cmd.ExecuteNonQuery();
cmd.CommandText = "CREATE INDEX IF NOT EXISTS idx_word_word ON word(id)";
cmd.ExecuteNonQuery();

在C＃中获取异常错误（接近“INDEX”：语法错误）

2 个答案: