Question

我编写了一个程序，用于输入用户输入（姓名，高中课程），当用户输入完成后，可以按下我创建的名为“Enter”的按钮。但是，为了使我的程序更整洁，我希望用户能够使用键盘上的回车键。

如何将当前链接到我已定义的'Enter'按钮的功能分配给键盘上的enter键，以便用户可以使用？

name_var = StringVar()
    def event_enter_1():
        self.Enter_1.config(state=(NORMAL if name_var.get() else DISABLED))

    name_var.trace('w', lambda name, index, mode: event_enter_1())
    enter_name = Entry(self, textvariable=name_var)
    enter_name.pack()
    enter_name.focus_set()



    def enter_button_1():
        if len(name_var.get()) > 10 or any(l not in string.ascii_letters for l in name_var.get()):
            tkMessageBox.showerror("Error", "Please enter a real name.")
        else:
            global student_name
            student_name = name_var.get()
            self.Enter_1.config(state="disabled")

            self.display_surname= tk.Label(self, width=40, height=2, text = "Now please enter your surname.")
            self.display_surname.pack(side="top", fill="both", expand=True)

            surname_var = StringVar()
            def event_enter_2():
                self.Enter_2.config(state=(NORMAL if surname_var.get() else DISABLED))
            surname_var.trace('w', lambda name, index, mode: event_enter_2())
            surname = Entry(self, textvariable=surname_var)
            surname.pack()
            surname.focus_set()

            def enter_button_2():
                if len(surname_var.get()) > 10 or any(l not in string.ascii_letters for l in surname_var.get()):
                    tkMessageBox.showerror("Error", "Please enter a real name.")
                else:
                    global student_surname
                    student_surname = surname_var.get()
                    self.Enter_2.config(state="disabled")

                    self.display_tutor = tk.Label(self, width=40, height=2, text = "Now please enter your tutor group.")
                    self.display_tutor.pack(side="top", fill="both", expand=True)

                    tutor_var = StringVar()
                    def event_enter_3():
                        self.Enter_3.config(state=(NORMAL if tutor_var.get() else DISABLED))
                    tutor_var.trace('w', lambda name, index, mode: event_enter_3())
                    tutor = Entry(self, textvariable=tutor_var)
                    tutor.pack()
                    tutor.focus_set()

                    def enter_button_3():
                        if tutor_var.get() not in ["5A1", "5A2", "5B1", "5B2", "5B3", "5C1", "5C2", "6A1", "6A2", "6B1", "6B2", "6C1", "6C2", "6C3"]:
                            tkMessageBox.showerror("Error", "Please enter a tutor group that exists.")
                        else:
                            global student_tutor_group
                            student_tutor_group = tutor_var.get()
                            self.Enter_3.config(state="disabled")
                            tkMessageBox.showinfo("Details Confirmation", "Thank you for entering your details. Now you can begin the quiz. Good luck!")
                            parent.question_1.config(state="normal")
                            parent.enter_name.config(state="disabled")
                            self.destroy


                self.Enter_3 = Button(self, text="Enter", width=10, command=enter_button_3)
                self.Enter_3.pack()
                self.Enter_3.config(state="disabled") #Initially the enter button is disbabled as the user hasn't started typing


        self.Enter_2 = Button(self, text="Enter", width=10, command=enter_button_2)
        self.Enter_2.pack()
        self.Enter_2.config(state="disabled") #Initially the enter button is disbabled as the user hasn't started typing


    self.Enter_1 = Button(self, text="Enter", width=10, command=enter_button_1)
    self.Enter_1.pack()
    self.Enter_1.config(state="disabled") #Initially the enter button is disbabled as the user hasn't started typing

如果这令人困惑，我很抱歉，我是OO编程的新手，所以也许有更有效的方法。非常感谢帮助。感谢

Answer 1

您需要添加绑定以将事件连接到函数。在这种情况下，事件为<Return>。你会这样做：

enter_name.bind('<Return>', enter_button_1)

当绑定触发时，它将使用一个参数调用该函数，该参数是描述该事件的对象。您需要修改您的函数才能接受该事件：

def enter_button_1(event=None)

如何为“Enter”按钮分配功能？

1 个答案: