Question

我正在努力了解如何创建＆amp;在C ++中处理一个unsigned char数组。如：

Array[0] = { new array of unsigned chars }
Array[1] = { new array of unsigned chars }
Array[2] = { new array of unsigned chars }
....and so on

我已经编写了下一个代码，但我觉得我做错了。代码工作正常，但我不知道我是否声明“缓冲区”以及如何删除缓存是正确的方法，或者它是否会产生内存泄漏。

#define MAX_BUFFER 10

unsigned char* cache[MAX_BUFFER];
bool cache_full = false;

void AddToCache(unsigned char *buffer, const size_t buffer_size)
{
    if (cache_full == true)
    {
        return;
    }

    for (int index = 0; index < MAX_BUFFER; index++)
    {
        if (cache[index] == NULL)
        {
            cache[index] = new unsigned char[buffer_size];
            memcpy(cache[index], buffer, buffer_size);
        }

        if (index < MAX_BUFFER - 1)
        {
            cache_full = true;
        }
    }
}

void ClearCache()
{
    for (int index = 0; index < MAX_BUFFER; index++)
    {
        if (cache[index] != NULL)
        {
            delete[] cache[index];
            cache[index] = NULL;
        }
    }

    cache_full = false;
}

bool IsCacheFull()
{
    return cache_full;
}

Answer 1

这有效吗？

memcpy(cache, buffer, buffer_size);

不应该。这将覆盖cache中buffer内容的所有指针。memcpy(cache[index], buffer, buffer_size);。在上下文中，这应该是：

cache_full

此外，每次添加到缓存时，您都会反复将true设置为AddToCache(unsigned char *buffer, const size_t buffer_size) { for (int index = 0; index < MAX_BUFFER; index++) { if (cache[index] == NULL) { cache[index] = new unsigned char[buffer_size]; memcpy(cache[index], buffer, buffer_size); return(index); // in case you want to find it again } } // if we get here, we didn't find an empty space cache_full = true; return -1; }。尝试：

{{1}}

无符号字符数组的C ++数组

1 个答案: