我在互联网上看过这样的课程, 头文件
#ifndef _COMMON_ARRAY_OBJECT_POOL_H_
#define _COMMON_ARRAY_OBJECT_POOL_H_
#include <stdint.h>
namespace easynet
{
class ArrayObjectPool
{
public:
/** construct
* @param elem_size : element size;
* @param elem_num : element number
*/
ArrayObjectPool(uint32_t elem_size, uint32_t elem_num);
~ArrayObjectPool();
uint32_t ElemSize(){return m_ElemSize;}
uint32_t Capacity(){return m_ElemNum;}
bool IsEmpty(){return m_FreeHead==NULL;}
void* Get();
bool Recycle(void *elem);
private:
void *m_Elements;
void *m_End;
void *m_FreeHead;
uint32_t m_ElemSize;
uint32_t m_ElemNum;
};
}
#endif //_COMMON_ARRAY_OBJECT_POOL_H_
cpp文件
#include <assert.h>
#include <stddef.h>
#include <stdlib.h>
#include "ArrayObjectPool.h"
namespace easynet
{
ArrayObjectPool::ArrayObjectPool(uint32_t elem_size, uint32_t elem_num)
{
m_ElemNum = elem_num;
if(elem_size < sizeof(void*))
m_ElemSize = sizeof(void*);
else
m_ElemSize = elem_size;
m_Elements = malloc(m_ElemSize*m_ElemNum);
m_End = (void*)((char*)m_Elements+m_ElemSize*m_ElemNum);
assert(m_Elements != NULL);
//construct list
int i;
void *node = m_Elements;
for(i=0; i<m_ElemNum-1; ++i)
{
*(void**)node = (void*)((char*)node+m_ElemSize);
node = *(void**)node;
}
*(void**)node = NULL;
m_FreeHead = m_Elements; //list head
}
ArrayObjectPool::~ArrayObjectPool()
{
free(m_Elements);
}
void* ArrayObjectPool::Get()
{
if(m_FreeHead == NULL)
return NULL;
void *temp = m_FreeHead;
m_FreeHead = *(void**)m_FreeHead;
return temp;
}
bool ArrayObjectPool::Recycle(void *elem)
{
if(elem<m_Elements || elem>=m_End)
return false;
*(void**)elem = m_FreeHead;
m_FreeHead = elem;
return true;
}
}
问题是我无法理解这意味着什么:
int i;
void *node = m_Elements;
for(i=0; i<m_ElemNum-1; ++i)
{
*(void**)node = (void*)((char*)node+m_ElemSize);
node = *(void**)node;
}
以及*(void**)
的含义是什么?谢谢!
答案 0 :(得分:2)
它将内存视为用户数据类型与union
之间的void*
。当块在空闲块列表中时,使用void*
。
您可以将其视为:
union ObjectInObjectPool
{
void* ptr_next_free_block;
UserType content;
};
然后该循环基本上正在做:
ObjectInObjectPool* node = m_Elements;
for(i=0; i<m_ElemNum-1; ++i) {
node->ptr_next_free_block = node + 1;
node = node->ptr_next_free_block;
}
除了程序员手工完成编译器的类型检查器通常所做的所有指针算法。
答案 1 :(得分:0)
void*
是指向无类型内存的指针值。当你*(void**)node = ...
时,它真正做的是*node = ...
。但是,对于后者,你试图给void
赋予一些东西,这对C ++的类型系统没有意义;你必须像前者一样把它投射到void**
,这样*node
将是void*
,而不是void
,你可以分配给它。 / p>
node = *(void**)node
只是node = *node
,但强制类型系统正常工作。它只是“node
将*node
内存的值分配为void*
”。