Question

如何使用oracle中的每个薪水显示每个部门的员工人数

类似这样的事情

department_id salar_equal_1000  salar_equal_20000 city_boston city_detroit city_none
10            2                 3                 2           1            2
20            1                 2                 1           2            0

表包含这样的数据

department_id   salary city
10              1000   boston
10              1000   boston
10              2000   detroit
10              2000   
10              2000   
20              1000   boston
20              2000   detroit
20              2000   detroit

我想我必须使用pivot声明，但我不确定需要一些帮助

Answer 1

试试这个：

select
    department_id, 
    sum(case when salary = 1000 then 1 else 0 end) as salar_equal_1000,
    sum(case when salary = 2000 then 1 else 0 end) as salar_equal_2000,
    sum(case when city   = 'boston' then 1 else 0 end) as city_boston,
    sum(case when city   = 'detroit' then 1 else 0 end) as city_detroit,
    sum(case when city   is null then 1 else 0 end) as city_none
from
    employees
group by department_id
order by department_id

再次编辑：

在这里查看小提琴：http://sqlfiddle.com/#!4/3564c/6

Answer 2

Hi please go through the following example, Might be it will help you.

如果您正在使用oracle10g，这是格式，如果有11g枢轴功能

WITH cte(dept_id,salary) AS (SELECT 10,1000 FROM dual
                                      UNION ALL
SELECT 10,1000 FROM dual
UNION ALL
                             SELECT 10,1000 FROM dual
                             UNION ALL
                             SELECT 20,1000 FROM dual
                             UNION ALL
                             SELECT 10,2000 FROM dual
                             UNION ALL
                             SELECT 10,2000 FROM dual
                             UNION ALL
                             SELECT 20,1000 FROM dual
                             UNION ALL
                             SELECT 20,2000 FROM dual
                             UNION ALL
                             SELECT 20,2000 FROM dual
                            ),


TEMP as(SELECT
    dept_id,
     count(salary) cnt,salary
FROM
    cte
GROUP BY salary, dept_id)

SELECT dept_id,sum(CASE WHEN salary=1000 THEN cnt ELSE 0 END)salary_1000,
sum(CASE WHEN salary=2000 THEN cnt ELSE 0 END) salary_2000 FROM TEMP
GROUP BY dept_id

Oracle pivot功能有两列

2 个答案: