我是以下查询来验证表单发布的登录信息。但每当我运行查询时,我都会收到内部服务器错误。我不确定我做错了什么。
<?php
if(isset($_POST["userName"]) && isset($_POST["password"])){
$userName = $_POST["userName"];
$password = $_POST["password"];
include "http://evocature.com/scripts/db_connect.php";
$results = mysql_query("SELECT id
FROM admins
WHERE userName = '$userName'
AND password ='$password' LIMIT 1");
$existCount = mysql_num_rows($results);
if($existCount == 1){
while($row = mysql_fetch_array($results)){
$id = $row["id"];
}
$_SESSION["id"] = $id;
$_SESSION["manager"] = $manager;
$_SESSION["password"] = $password;
header("Location: http://www.evocature.com/admin/index.php");
exit();
}
else{
echo 'Invalid Information';
exit();
}
}
答案 0 :(得分:0)
我相信你可以包含http页面。不会用这种方法。