您好我正在将职业转变为计算机编程。我还在上大学。我必须将以下LINQ查询从方法语法更改为查询语法。让我得到的是方法查询的2个步骤。首先,它获得一个teamId,然后根据上下文并使用teamId返回一个列表。我对如何将其转换为查询方法感到困惑。大多数问题都是关于从查询语法到方法的。
有人可以帮忙吗?
public IEnumerable<TemplateView> GetTemplates(Guid userId, int languageId)
{
using (DigigateEntities context = new Models.DigigateEntities())
{
var teamId = context
.TeamMembers
.Include("Team")
.FirstOrDefault(c => c.UserId == userId)
.Team.Id;
return context
.TeamTemplates.Include("Template")
.Where(c => c.TeamId == teamId)
.Select(c => c.Template)
.Where(c => c.StatusId == 1/*Active*/)
.Select(k => new TemplateView
{
TemplateName = k.Name,
Id = k.Id,
IsCustom = k.Custom,
TypeId = k.TypeId,
TypeName = k.TemplateType.Description,
FileName = k.FileName,
TemplateImage = "test.png",
LanguageId = k.LanguageId,
LanguageName = k.Language.Name,
CreateDate = k.CreateDate
}).ToList();
}
}
答案 0 :(得分:0)
第一个很直接。我将查询的执行延迟到最后。由于您在访问.FirstOrDefault().Team.Id;
var teamId = (from c in context.TeamMembers.Include("Team")
where c.UserId == userId
select c.Team.Id).FirstOrDefault();
这个只需要使用into
来继续查询语句
return (from c in context.TeamTemplates.Include("Template")
where c.TeamId == teamId
select c.Template into k
where k.StatusId == 1
select new TemplateView
{
TemplateName = k.Name,
Id = k.Id,
IsCustom = k.Custom,
TypeId = k.TypeId,
TypeName = k.TemplateType.Description,
FileName = k.FileName,
TemplateImage = "test.png",
LanguageId = k.LanguageId,
LanguageName = k.Language.Name,
CreateDate = k.CreateDate
}).ToList();
答案 1 :(得分:0)
public IEnumerable<TemplateView> GetTemplates(Guid userId, int languageId)
{
using (DigigateEntities context = new Models.DigigateEntities())
{
var teamId = (from tm in context.TeamMembers.Include("Team")
where tm.UserId==userId
select tm.Id).FirstOrDefault();
IEnumerable<TemplateView> result = from k in (from tmp in context.TeamTemplates.Include("Template")
select tmp.Template)
where k.StatusId==1
select new
{
TemplateName = k.Name,
Id = k.Id,
IsCustom = k.Custom,
TypeId = k.TypeId,
TypeName = k.TemplateType.Description,
FileName = k.FileName,
TemplateImage = "test.png",
LanguageId = k.LanguageId,
LanguageName = k.Language.Name,
CreateDate = k.CreateDate
};
return result;
}