Question

我是shell脚本的新手。谁能告诉我上面拆分文字的方法。这里我需要的值，如果真的可以在shell脚本中存储在数组中？

=============示例文本=====================

Reading application configuration data...


Beginning interaction for module default...
default: ['1', '52', '53', '54', 55-vm, '55', '56', '57', '58', '59', '60', '61',
  '62', '63', '65', '66', '67', ah-builtin-python-bundle, export-backend, export,
  lab, stage-test, test]

Success.
Cleaning up temporary files for module default...

============================================

============== RESULT ========================

  ['1', '52', '53', '54', 55-vm, '55', '56', '57', '58', '59', '60', '61',
  '62', '63', '65', '66', '67', ah-builtin-python-bundle, export-backend, export,
  lab, stage-test, test]

============================================

Answer 1

这应该让你开始。但是它只会提取单行上的数组，只有每行只有一个数组时它才有用。

ARRAYTXT=$(sed -nr 's/.*(\[.*\]).*/\1/p' file.txt)
ARRAY=($(echo $ARRAYTXT | sed -r "s/'([^']*)'/\1/g;s/([^,]*),/\1/g;s/\[//;s/\]//"))
echo ${a[*]}

结果：

1 52 53 54 55-vm 55 56 57 58 59 60 61 62 63 65 66 67 ah-builtin-python-bundle export-backend export lab stage-test test

Answer 2

我使用awk转换数据，并将其存储在数组中

ary=( $( 
    awk -v RS= '
        match($0, /default: \[(.+)\]/, a) { gsub(/[\n,]/,"",a[1]); print a[1] }
    ' sample.txt
) )

并验证数组的内容：

$ for i in "${!ary[@]}"; do echo "$i  ${ary[i]}"; done
0  '1'
1  '52'
2  '53'
3  '54'
4  55-vm
5  '55'
6  '56'
7  '57'
8  '58'
9  '59'
10  '60'
11  '61'
12  '62'
13  '63'
14  '65'
15  '66'
16  '67'
17  ah-builtin-python-bundle
18  export-backend
19  export
20  lab
21  stage-test
22  test

如何使用shell脚本拆分文本并获取数组值？

2 个答案: