Question

我有一个功能，我需要点击和立方体一次，立方体将旋转到那一侧，然后当我点击并按住2秒将转到第五页或当我点击没有保持将启动立方体旋转

这就是我所拥有的

var numPressed:Number = 0
    function side6(event:MouseEvent):void {
        numPressed++;
            if (numPressed % 2) {
                SimpleZSorter.sortClips(container);
                TweenLite.to(container, 1, {rotationX:-8,rotationY:193});
                addEventListener(Event.ENTER_FRAME, rotateStop);
                removeEventListener(Event.ENTER_FRAME, rotateThis);
            }else if (NEED SOEMTHING HERE TO DETECT MOSUE HOLD AFTER SECONDS) {
                gotoAndStop(5);
            }
            else{
                addEventListener(Event.ENTER_FRAME, rotateThis);
            }
    }

如果按下奇数或偶数，意思是atump计算，意味着1次点击将停止立方体旋转，2将再次启动，第三次将停止，如果等等，我需要这样做以保持这样的行为。

我在第二个if语句中需要一些东西，除了让它在按住鼠标时工作正常。

任何帮助表示赞赏

伊恩

Answer 1

我建议您使用MouseEvent.DOWN和MouseEvent.UP并存储Date.time。

EG：这组函数将跟踪MouseEvent.DOWN和MouseEvent.UP事件之间经过的毫秒数。

private var mouseDownTime:Number = NaN,mouseUpTime:Number = NaN;

private function init():void
{
    yourCubeObject.addEventListener(MouseEvent.DOWN,onMouseDown);
    yourCubeObject.addEventListener(MouseEvent.UP,onMouseUp);
    yourCubeObject.addEventListener(MouseEvent.OUT,onMouseOut);
}
private function onMouseOut(event:MouseEvent):void
{
    mouseDownTime = mouseUpTime = NaN;//clear storage
}
private function onMouseDown(event:MouseEvent):void
{
    mouseDownTime = new Date().time;//store system time in milliseconds since epoc
}
private function onMouseUp(event:MouseEvent):void
{
    mouseUpTime = new Date().time;
    if (!isNaN(mouseDownTime))//avoid error case where mouse went down outside object
    {
        if ((mouseUpTime - mouseDownTime) >= 2000)
        {
            //mouse held down for more the 2 seconds, your function here.
        }
    }
    onMouseOut(event);//reset counters
}

单击保留时的Actionscript 3计时器

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