Question

尝试让我的if允许用户输入名称或随机选择，但无论输入什么，它都会转到名称输入？

有什么想法吗？

这是我的代码：

import random
import os
names = "Balo", "Bandugl", "Baroro", "Cag", "Charoth", "Dugling", "Dulko", "Fangot", "Gormath", "Varth", "Ugort", "Ogong", "Tuli", "Corg", "Chau", "Korg", "Salath", "Wegia",        "Wecha", "Moroth", "Kangir", "Bethindu", "Duak", "Fagoot", "Penam"
rand_name = random.choice(names)

#Character creation (1)#
if input("Would you like to choose a name?: ") == "Y" or "y" or "yes" or "YES":
    print("")
    c1 = {"Name":input("Name: ")}
else:
    c1 = {"Name":rand_name}
print(c1)

提前致谢！

Answer 1

在你的行

if input("Would you like to choose a name?: ") == "Y" or "y" or "yes" or "YES":

您不能链接这样的值，它将按如下方式进行评估

( input("Would you like to choose a name?: ") == "Y") or ("y") or ("yes") or ("YES")

在这种情况下，or ("y")将返回True，因为非空字符串都已经过评估True

你必须尝试：

if input("Would you like to choose a name?: ") in ["Y", "y", "yes", "YES"]:

然后它会检查输入是"Y"，"y"，"yes"还是"YES"值

之一

或者您可以使用str.upper()使您的选项列表不那么拥挤：

if input("Would you like to choose a name?: ").upper() in ["Y", "YES"]:

Answer 2

if input("Would you like to choose a name?: ").lower() in ("y", "yes"):

Answer 3

你的比较是错误的。

if input("Would you like to choose a name?: ") in ("Y", "y", "yes", "YES"):

了解您的错误：

>>> "a" == "Y" or "y"
'y'
>>> "Y" == "Y" or "y"
True

Answer 4

在3

中使用raw_input（2.7）输入

import random
import os
names = "Balo", "Bandugl", "Baroro", "Cag", "Charoth", "Dugling", "Dulko", "Fangot", "Gormath", "Varth", "Ugort", "Ogong", "Tuli", "Corg", "Chau", "Korg", "Salath", "Wegia",        "Wecha", "Moroth", "Kangir", "Bethindu", "Duak", "Fagoot", "Penam"
rand_name = random.choice(names)

#Character creation (1)#
if raw_input('Enter your name: ').upper() in ["Y" , "YES" ]:
    print("")

    c1 = {"Name":raw_input("Name: ")}
else:
    c1 = {"Name":rand_name}
print(c1)

如果语句在检查输入值时未按预期工作

4 个答案: