Question

我试图仅在字符串中获得3个单词的单词频率。例如：

$ string =“这是一个示例文本。它是一个示例文本，用作示例。”;

我想要输出：

“是一个样本”（2）

“示例文本”（2）

....等等

提前致谢。

Answer 1

用空格作为分隔符来爆炸句子并循环。

<?php
$string = "This is a sample text. It is a sample text used as an example.";
$arr = explode(' ',$string);
$i=0;
foreach($arr as $k=>$v)
{
echo $arr[$i]." ".$arr[$i+1]." ".$arr[$i+2]."<br>";
$i++;
}

<强> OUTPUT :

This is a
is a sample
a sample text.
sample text. It
text. It is
It is a
is a sample
a sample text
sample text used
.....

Answer 2

$string = "This is a sample text. It is a sample text used as an example.";
$words = preg_split('/\W/', $string);
$wordsPerRow = 3;


$offset = 0;
while ($offset < count($words)) {
    print implode(' ', array_slice($words, $offset, $wordsPerRow)).PHP_EOL;
    $offset += $wordsPerRow;
}

在字符串中获取3个字数

2 个答案: