Question

大家好，以下是我的表

Table:- Project
         -Project_ID (primary)
         -ProjectName

 Table:- Task
        -Task_ID ( primary)
        -project_ID
        -TaskName

我想从项目表中选择任务名称。我该怎么做？

Answer 1

mysql_query("select TaskName from Project left join Task on Project.Project_ID = Task.project_ID")

Answer 2

<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$result = mysqli_query($con,"select P.Project_ID, P.ProjectName, T.Task_ID,".
  " T.TaskName from Task T".
  " left outer join Project P on P.Project_ID=T.project_ID");

while($row = mysqli_fetch_array($result))
  {
  echo $row['Project_ID'] . " " . $row['Project_ID'];
  echo $row['ProjectName'] . " " . $row['ProjectName'];
  echo $row['Task_ID'] . " " . $row['Task_ID'];
  echo $row['TaskName '] . " " . $row['TaskName '];
  echo "<br>";
  }

mysqli_close($con);
?>

如何使用php从mysql数据库中选择Row

2 个答案: