Question

我有一份工作，从某一天到一周的某一天。例如（周一至周六）。当停止日期时，我能够覆盖案例＆gt; starday for eg-startday-＆gt; Monday stopDay-＆gt; Saturday 但当范围变为星期三到星期一时，我无法涵盖这种情况。

private boolean isNotWindow(DateTime todayDate) {
        final int hr = 3600;
        final int min = 60;
        int stopDay =
                Integer.parseInt(ShipmentTrackingEmailProperties.getInstance().getProperty(
                        ShipmentTrackingEmailProperties.SHIPMENT_EMAIL_STOP_DAY));
        int startDay =
                Integer.parseInt(ShipmentTrackingEmailProperties.getInstance().getProperty(
                        ShipmentTrackingEmailProperties.SHIPMENT_EMAIL_START_DAY));

        if(stopDay<startDay)
        {
            //Not able to figure out??????
        }
        if (todayDate.getDayOfWeek() >= stopDay) {
            String stopTime =
                    ShipmentTrackingEmailProperties.getInstance().getProperty(ShipmentTrackingEmailProperties.SHIPMENT_EMAIL_STOP_TIME);
            String[] array = stopTime.split(":");
            System.out.println(array[0] + "  " + array[1] + "   " + array[2]);
            int hh = Integer.parseInt(array[0]);
            int mm = Integer.parseInt(array[1]);
            int ss = Integer.parseInt(array[2]);
            int tSec = todayDate.getHourOfDay() * hr + todayDate.getMinuteOfDay() * min + todayDate.getSecondOfDay();
            int sSec = hh * hr + mm * min + ss;
            if (tSec > sSec) {
                     return true;
            }
        }
        if (todayDate.getDayOfWeek() <= startDay) {
            String startTime =
                    ShipmentTrackingEmailProperties.getInstance().getProperty(ShipmentTrackingEmailProperties.SHIPMENT_EMAIL_START_TIME);
            String[] array = startTime.split(":");
            int hh = Integer.parseInt(array[0]);
            int mm = Integer.parseInt(array[1]);
            int ss = Integer.parseInt(array[2]);
            int tSec = todayDate.getHourOfDay() * hr + todayDate.getMinuteOfDay() * min + todayDate.getSecondOfDay();
            int sSec = hh * hr + mm * min + ss;
            if (tSec <= sSec) {
                LOG.info("Not a valid day to send mail ." + todayDate.getDayOfWeek());
                 return true;
            }
        }
             LOG.info("Valid day to send mail ." + todayDate.getDayOfWeek());
         return false;
    }

如果日期不在一个范围内，则此函数返回true。所以如何覆盖案例时 stopDay＆lt;朝九特派

Answer 1

您可以使用此功能检查范围内的日期

private static boolean inRange(int startDay, int stopDay, int checkMe) {
    if(startDay==stopDay) {
           if(startDay==checkMe){
                   return true;
           } else {
                   return false;
           }
    }
    while(startDay!=stopDay) {
        if(startDay==checkMe || stopDay==checkMe) {
            return true;
        }
        if(startDay==7) {
            startDay =0;
        }
        startDay++;
    }
    return false;
}

希望它有所帮助。

Answer 2

你需要：

if startday<stopday then
    if the day is in the interval (startday,stopday) then OK
    else NotOk
else 
    if the day is not in the interval (startday,stopday) then OK
    else NotOk

它可以更容易完成：

If((day-startday)*(stopday-day)*(stopday-startday)>=0) then OK
else NotOk

如何检查一天是否在一个范围之间？

2 个答案: