Question

我想将数据框导出到Excel并根据特定规则突出显示单元格。我不认为this answer类似的问题是正确的。我认为这是可能的，我认为我接近使用CellStyle包的xlsx函数。

下面我概述了我尝试过的内容。大多数想法来自包帮助文件。当我尝试将我创建的样式应用于符合条件的单元格时，我会一路走到最后并得到错误。我收到错误：Error in .jcall(cell, "V", "setCellStyle", cellStyle$ref) : RcallMethod: invalid object parameter。

library(xlsx)
# create data 
  cols <- sample(c(1:5), 1) # number of columns to vary to mimic this unknown
  label <- rep(paste0("label ", seq(from=1, to=10)))
  mydata <- data.frame(label)
  for (i in 1:cols) {
    mydata[,i+1] <- sample(c(1:10), 10)
  }
# exporting data.frame to excel is easy with xlsx package
  sheetname <- "mysheet"
  write.xlsx(mydata, "mydata.xlsx", sheetName=sheetname)
  file <- "mydata.xlsx"
# but we want to highlight cells if value greater than or equal to 5
  wb <- loadWorkbook(file)              # load workbook
  fo <- Fill(backgroundColor="yellow")  # create fill object
  cs <- CellStyle(wb, fill=fo)          # create cell style
  sheets <- getSheets(wb)               # get all sheets
  sheet <- sheets[[sheetname]]          # get specific sheet
  rows <- getRows(sheet)                # get rows
  cells <- getCells(rows)               # get cells
  values <- lapply(cells, getCellValue) # extract the values
# find cells meeting conditional criteria 
  highlight <- "test"
  for (i in names(values)) {
    x <- as.numeric(values[i])
    if (x>=5 & !is.na(x)) {
      highlight <- c(highlight, i)
    }    
  }
  highlight <- highlight[-1]
# apply style to cells that meet criteria
  if (length(highlight)>0) {            # proceed if any cells meet criteria
    setCellStyle(cells[highlight], cs)  # DOES NOT WORK
  }
# save
  saveWorkbook(wb, file)

更新我也试过了：

if (length(highlight)>0) {                # proceed if any cells meet criteria
    for (h in 1:length(highlight)) {
      setCellStyle(cells[highlight[h]], cs)  # DOES NOT WORK
    }
  }

但我收到错误：Error in .jcall(cell, "V", "setCellStyle", cellStyle$ref) : RcallMethod: cannot determine object class

Answer 1

试一试。我更改了一些内容，包括对Fill调用的轻微更改，并将包含的单元格限制为考虑使用数字数据。我使用lapply来应用条件格式。

  cols <- sample(c(1:5), 1) # number of columns to vary to mimic this unknown
  label <- rep(paste0("label ", seq(from=1, to=10)))
  mydata <- data.frame(label)
  for (i in 1:cols) {
    mydata[,i+1] <- sample(c(1:10), 10)
  }
# exporting data.frame to excel is easy with xlsx package
  sheetname <- "mysheet"
  write.xlsx(mydata, "mydata.xlsx", sheetName=sheetname)
  file <- "mydata.xlsx"
# but we want to highlight cells if value greater than or equal to 5
  wb <- loadWorkbook(file)              # load workbook
  fo <- Fill(foregroundColor="yellow")  # create fill object
  cs <- CellStyle(wb, fill=fo)          # create cell style
  sheets <- getSheets(wb)               # get all sheets
  sheet <- sheets[[sheetname]]          # get specific sheet
  rows <- getRows(sheet, rowIndex=2:(nrow(mydata)+1)     # get rows
                                                         # 1st row is headers
  cells <- getCells(rows, colIndex = 3:(cols+3))       # get cells
# in the wb I import with loadWorkbook, numeric data starts in column 3
# and the first two columns are row number and label number

  values <- lapply(cells, getCellValue) # extract the values

# find cells meeting conditional criteria 
  highlight <- "test"
  for (i in names(values)) {
    x <- as.numeric(values[i])
    if (x>=5 & !is.na(x)) {
      highlight <- c(highlight, i)
    }    
  }
  highlight <- highlight[-1]

lapply(names(cells[highlight]),
       function(ii)setCellStyle(cells[[ii]],cs))

saveWorkbook(wb, file)

Answer 2

古老的问题，但对于仍在研究此主题的人来说：

在openxlsx软件包中，有一个函数使此操作变得更加容易-conditionalFormatting（）

下面是一个示例：

library(openxlsx)

wb <- createWorkbook()
addWorksheet(wb, "cellIs")

## rule applies to all each cell in range
writeData(wb, "cellIs", -5:5)
writeData(wb, "cellIs", LETTERS[1:11], startCol=2)
conditionalFormatting(wb, "cellIs", cols=1, rows=1:11, rule="!=0", style = negStyle)
conditionalFormatting(wb, "cellIs", cols=1, rows=1:11, rule="==0", style = posStyle)

saveWorkbook(wb, "conditionalFormattingExample.xlsx", TRUE)

您可以在此处阅读有关内容，并查看它可以执行的许多其他类型的条件突出显示： https://rdrr.io/cran/openxlsx/man/conditionalFormatting.html

Answer 3

我使用此功能已经有一段时间了。是的，应该可以保存条件格式。我的（旧）代码如下。希望它可以帮到你。

file.name <- paste('loadings.',state$data,'.xls', sep = "")
wb <- loadWorkbook(file.name, create = TRUE)

createSheet(wb, name = 'loadings')
clearSheet(wb, sheet = 'loadings')

Variables <- rownames(df)
df.loadings <- cbind(Variables,df)
df.loadings[,'Communality'] <- NULL
writeWorksheet(wb,df.loadings[,-1], sheet = 'loadings', rownames = 'Variables', startRow = 1, startCol = 1)

max.loading <- createCellStyle(wb)
setFillPattern(max.loading, fill = XLC$"FILL.SOLID_FOREGROUND")
setFillForegroundColor(max.loading, color = XLC$"COLOR.SKY_BLUE")
maxVal <- apply(abs(df.loadings[,-1]),1,max)
maxValIndex <- which(abs(df.loadings[,-1]) == maxVal, arr.ind = TRUE)
setCellStyle(wb, sheet = "loadings", row = maxValIndex[,'row']+1, col = maxValIndex[,'col']+1, cellstyle = max.loading)

df.corr <- data.frame(cor(f.data))
df.corr <- cbind(Variables,df.corr)
createSheet(wb, name = 'correlations')
clearSheet(wb, sheet = 'correlations')
writeWorksheet(wb, df.corr, sheet = 'correlations', startRow = 1, startCol = 1)
corr <- createCellStyle(wb)
setFillPattern(corr, fill = XLC$"FILL.SOLID_FOREGROUND")
setFillForegroundColor(corr, color = XLC$"COLOR.SKY_BLUE")
corrIndex <- which(abs(df.corr[,-1]) > .3 & df.corr[,-1] != 1 , arr.ind = TRUE)
setCellStyle(wb, sheet = "correlations", row = corrIndex[,'row']+1, col = corrIndex[,'col']+1, cellstyle = corr)

saveWorkbook(wb)

if(.Platform$OS.type == "unix") {
    execute(paste("browseURL(\"",getwd(),'/',file.name,"\", browser = '/usr/bin/open')",sep=''))
} else {
    execute(paste("browseURL(\"",getwd(),'/',file.name,"\", browser = NULL)",sep=''))
}

使用条件格式通过xlsx将数据框导出到Excel

3 个答案: