到目前为止,这是我的代码。我对java.lang
例外感到困惑。我是编程新手。我的代码有什么问题?
import javax.swing.*;
import java.lang.Character;
import java.io.*;
public class HWCent
{
public static void main(String args [])throws IOException
{
String vince = JOptionPane.showInputDialog("Enter Your File path :");
String c = JOptionPane.showInputDialog("Enter a character");
int NOc = 0;
for(int v = 1; v<=c.length(); v++)
{
char x = c.charAt(v);
if(Character.isSpaceChar(x))
{
NOc++;
}
char z = c.charAt(v);
if(Character.isLetter(z))
{
NOc++;
}
}
File file = new File(vince);
if(!file.exists())
{
JOptionPane.showMessageDialog(null,"Wrong file path !");
}
else
{
JOptionPane.showMessageDialog(null, "The Number of Characters in "+ c +" is "+ NOc);
try
{
RandomAccessFile gui = new RandomAccessFile(file," ");
gui.writeBytes("The number of Characters in "+ c + " is " +NOc);
gui.close();
}
catch(IOException m)
{
System.out.print(m.getMessage());
}
}
}
}
答案 0 :(得分:5)
如果你有一个长度为6的字符串,那么你可以访问的最后一个索引是5.当你使用它时
for(int v = 1; v <= c.length(); v++)
您最终尝试访问不存在的索引6。只需改为
for(int v = 0; v < c.length(); v++) // Notice < instead of <=
另外,请注意我已将v = 1
更改为v = 0
。 Java字符串从0开始编制索引,因此您需要从那里开始访问字符串的第一个字符。