如何在拖动节点后将节点连接到d3树

Question

我有一个我渲染的d3树。要求是我可以将节点拖到另一个位置，以便用户可以单独展开该部分。

我可以添加拖拽代码，但在拖动完成后，父级和子级之间的链接就消失了。

让我知道如何让这个工作。我附上了渲染代码的图像。

var m = [20, 120, 20, 120],
    w = 1280 - m[1] - m[3],
    h = 800 - m[0] - m[2],
    i = 0,
    root;

var tree = d3.layout.tree()
    .size([h, w]);

var diagonal = d3.svg.diagonal()
    .projection(function(d) { return [d.y, d.x]; });

var vis = d3.select("#body").append("svg:svg")
    .attr("width", w + m[1] + m[3])
    .attr("height", h + m[0] + m[2])
    .append("svg:g")
    .attr("transform", "translate(" + m[3] + "," + m[0] + ")");

d3.json("d3/flare.json", function(json) {
  root = json;
  root.x0 = h / 2;
  root.y0 = 0;

  function toggleAll(d) {
    if (d.children) {
      d.children.forEach(toggleAll);
      toggle(d);
    }
  }

  // Initialize the display to show a few nodes.
  root.children.forEach(toggleAll);
  update(root);

});

function update(source) {

  var duration = d3.event && d3.event.altKey ? 5000 : 500;    

  // Compute the new tree layout.
  var nodes = tree.nodes(root).reverse();

  // Normalize for fixed-depth.
  nodes.forEach(function(d) { d.y = d.depth * 180; });

  // Update the nodes…
  var node = vis.selectAll("g.node")
      .data(nodes, function(d) { return d.id || (d.id = ++i); });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("svg:g")
      .attr("class", "node")
      .attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
      .on("click", function(d) { toggle(d); update(d); });

  nodeEnter.append("svg:circle")
      .attr("r", 1e-6)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; })
       .call( drag);

  nodeEnter.append("svg:text")
      .attr("x", function(d) { return d.children || d._children ? -30 : 30; })
      .attr("dy", ".35em")
      .attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
      .text(function(d) { return d.name; })
      .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });

  nodeUpdate.select("circle")
      .attr("r", 20)
      .style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });

  nodeUpdate.select("text")
      .style("fill-opacity", 1);

  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
      .duration(duration)
      .attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
      .remove();


  // Update the links…
  var link = vis.selectAll("path.link")
      .data(tree.links(nodes), function(d) { return d.target.id; });

  // Enter any new links at the parent's previous position.
  link.enter().insert("svg:path", "g")
      .attr("class", "link")
      .attr("d", function(d) {
        var o = {x: source.x0, y: source.y0};
        return diagonal({source: o, target: o});
      })
      .style("stroke-width", function(d) {

        if(d.target.weight == undefined) {
            return "1px";
        }
        else {
            return (d.target.weight % 5 * 5) + "px";
        }

      })
      .style("stroke", function(d) {
        return "#CD1";
      })
      .transition()
      .duration(duration)
      .attr("d", diagonal);

  // Transition links to their new position.
  link.transition()
      .duration(duration)
      .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
      .duration(duration)
      .attr("d", function(d) {
        var o = {x: source.x, y: source.y};
        return diagonal({source: o, target: o});
      })
      .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });

}

  var drag = d3.behavior.drag().on("drag", function( d, i) {

    var selection = d3.selectAll( '.selected');

    if( selection[0].indexOf( this)==-1) {
        selection.classed( "selected", false);
        selection = d3.select( this);
        selection.classed( "selected", true);
    } 

    selection.attr("transform", function( d, i) {

        var coordinates = [0, 0];
        coordinates = d3.mouse(this);
        var x = coordinates[0];
        var y = coordinates[1];

        return "translate(" + [ x, y ] + ")"
    })

    // reappend dragged element as last 
    // so that its stays on top 
    this.parentNode.appendChild( this);
    d3.event.sourceEvent.stopPropagation();

    // Update the links…
    var link = vis.selectAll("path.link");

      // Enter any new links at the parent's previous position.
      link.style("stroke-width", function(d) {
            return "20px"
          })
      .style("stroke", function(d) {
        return "#CD1";
      })
      .transition()
      .duration(1000)
      .attr("d", diagonal);

    update(root);

  });

// Toggle children.
function toggle(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  } else {
    d.children = d._children;
    d._children = null;
  }
}

Answer 1

您实际上正在更新拖动功能中的链接，但他们使用.x和.y数据属性来确定位置。当您更新节点的位置时，您只需设置翻译而不更新数据。要修复，也要更新数据：

selection.attr("transform", function(d, i) {
    var coordinates = d3.mouse(this);
    d.x = coordinates[0];
    d.y = coordinates[1];

    return "translate(" + [ d.x, d.y ] + ")"
})