Question

我希望将当前的7天日历更改为5天日历。我的7天是从周日到周六，我希望将它改为星期一到星期五。

从我提到的两个主要方法：

-Hide both Sunday and Saturday columns using css.
-Rerun script to exclude Sunday and Saturday, calculating the dates again.

我已经看过两种方式而且无法理解它是如何工作的，我正在寻求帮助。

createCalendar（）

calendarString = '';
calendarString += '<table width="100%" height="425" data-role="table" border="1" bordercolor="#c0c0c0" cellpadding="0" cellspacing="0">';
calendarString += '<tr>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Sun<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Mon<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Tue<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Wed<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Thu<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Fri<\/td>';
calendarString += '<td bgcolor=\"#DDDDDD\" align=\"center\" valign=\"center\" width=\"40\" height=\"22\">Sat<\/td>';
calendarString += '<\/tr>';
thisDate == 1;

for (var i = 1; i <= 6; i++) 
{
    calendarString += '<tr>';
        for (var x = 1; x <= 7; x++) 
            {
                daycounter = (thisDate - firstDay)+1;
                thisDate++;
                if ((daycounter > numbDays) || (daycounter < 1)) 
                    {
                        calendarString += '<td align=\"center\" bgcolor=\"#888888\" height=\"30\" width=\"40\">&nbsp;<\/td>';
                    } 
                    else 
                        {
                            if (checkevents(daycounter,monthNum,yearNum,i,x) || ((todaysDay == x) && (todaysDate == daycounter) && (todaysMonth == monthNum)))
                                {
                                    if ((todaysDay == x) && (todaysDate == daycounter) && (todaysMonth == monthNum)) 
                                        {
                                            tempweek = i;
                                            tempdayofweek = x;
                                            calendarString += '<td style=\"vertical-align: top;\" bgcolor=\"#AAFFAA\" height=\"30\" width=\"40\" onClick=showevents(' + daycounter + ',' + monthNum + ',' + yearNum + ',' + i + ',' + x + ')>' + daycounter + '<\/td>';
                                        }
                                else    
                                    {
                                    calendarString += '<td style=\"vertical-align: top;\" bgcolor=\"#FFFFC8\" height=\"30\" width=\"40\" onClick=showevents(' + daycounter + ',' + monthNum + ',' + yearNum + ',' + i + ',' + x + ')>' + daycounter + '<div id="amountevent" style="padding-left:5px;max-height:8px; height:8px; width:30px; max-width:30px;white-space: nowrap;">' + displayeventnumber(daycounter, monthNum, yearNum) + '</div><\/td>';


                                    }
                            } 
                            else 
                                {
                                    calendarString += '<td style=\"vertical-align: top;\" bgcolor=\"#f9f9f9\" height=\"30\" width=\"40\">' + daycounter + '<\/td>';         
                                }
                        }
                }
            calendarString += '<\/tr>';
        }
    calendarString += '<\/table>';
    var object=document.getElementById('calendar');
    object.innerHTML= calendarString;
    thisDate = 1;

Answer 1

假设内部for循环中的所有内容都像宣传的那样工作，你可以这样做：

for (var i = 1; i <= 6; i++) {
    thisDate++ //Sunday
    calendarString += '<tr>'

    for (var x = 2; x <= 6; x++) {
        //all of that inner for loop code
    }

    calendarString += '</tr>'
    thisDate++ //Saturday
}

另外：thisDate == 1应该是：thisDate = 1在初始for循环之前的顶部。

Answer 2

CSS解决方案更为复杂（对于你的凌乱代码和跳跃2天的问题），但修改JS应该更好。

它们是第一个和最后一个元素，所以你可以这样做：

table td:first-child, table td:last-child {
   display: none;
}

问题：last-child在旧浏览器上不起作用（IE <9）。解决方案：jQuery跨浏览器工作：

$('table td:first-child, table td:last-child').remove()

注意：您确定是thisDate == 1;吗？还是一个=？

将7天日历更改为5天日历

2 个答案: