Question

我有以下数字：

0,37,38,39,40,43,54,55,56,57,60,67,68,71,76,79,81,84,91,97,105,111,116,117,37,38,39,40 ，43,54,55,56,57,60,67,68,71,76,79,81,84,88,91,97,105,111,116,117,118,119,37,38,39,40,43,54,55,56,57 ，60,67,68,71,76,79,81,84,88,91,97,105,111,116,117,120,121,124,130,139,143,151,155,157,167,172,182,187,189,190,195,200,201,227,228,230,232,233,234,235,236,238,239,240,241,242,243,244,246,247,281,282,283,284,285,286,287,289,290,316,331,341,342,343,344,351,369,370,396,399,403,404,405,406,407

我想知道有多少号码。例如......

SELECT COUNT (11,12,13,14,15,16,17,18,19,20)

...应该返回10个数字。有没有办法使用MySQL做到这一点？

Answer 1

使用length和replace功能的组合。

mysql> SELECT length(replace('1,2,3,4,5,6,7,8,9,0', ',', '' ));
+--------------------------------------------------+
| length(replace('1,2,3,4,5,6,7,8,9,0', ',', '' )) |
+--------------------------------------------------+
|                                               10 |
+--------------------------------------------------+
1 row in set (0.33 sec)

然而，你必须处理字符串中存在的其他字符。

我还希望你要求的是数字位数而不是字符串中CSV的数量。

Answer 2

实际上我认为你真的在寻找：

SELECT length('43,54,55,56,57,60,67,68,71') - 
       length(replace('43,54,55,56,57,60,67,68,71', ',' ,'')) + 1

以上内容将返回9。

如果我要使用

SELECT length(replace('43,54,55,56,57,60,67,68,71', ',', '' ));

它会返回18这是不正确的，除非你在逗号以外的唯一数量的字符之后。

计算数字的数量

2 个答案: