Question

帮助我了解如何使用Intent。通过代码中的“意图”使用无法进入下一个期望的活动，如下所示

     public class GetIn extends Activity {
EditText editName;
EditText editPsscd;
EditText editSport;
EditText editTeam;
Button button;
final Context context = this;
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_get_in);
    button = (Button)findViewById(R.id.button1);
    editName = (EditText)findViewById(R.id.editText1);
    editPsscd = (EditText)findViewById(R.id.editText2);
    editSport = (EditText)findViewById(R.id.editText3);
    editTeam = (EditText)findViewById(R.id.editText4);
    button.setOnClickListener(new View.OnClickListener() {

        public void onClick(View v) {
            Intent intent = new Intent(context,Success.class);

            intent.putExtra("Name",editName.getText().toString());
            intent.putExtra("Passcode",editPsscd.getText().toString());
            intent.putExtra("Sports",editSport.getText().toString());
            intent.putExtra("Team", editTeam.getText().toString());
            startActivity(intent);
        }
    });
}

上下文的使用是否有效？这是“Success.java”文件

    public class Success extends GetIn {
public void onCreate(Bundle savedInstanceState){
    TextView textName;
    TextView textSport;
    TextView textTeam;

    super.onCreate(savedInstanceState);
    setContentView(R.layout.success);

    Intent intent = getIntent();
    textName=(TextView)findViewById(R.id.textView1);
    textName.setText("Your name is "+intent.getStringExtra("Name").toString());
    textSport=(TextView)findViewById(R.id.textView2);
    textSport.setText("Your Favourite sports is "+intent.getStringExtra("Sport").toString());
    textTeam=(TextView)findViewById(R.id.textView3);
    textTeam.setText("Your Favourite team is "+intent.getStringExtra("Team").toString());

}

}

Answer 1

你应该替换这个

Intent intent = new Intent(context,Success.class);

使用

Intent intent = new Intent(GetIn.this,Success.class);
Bundle b = new Bundle();
b.putString("Name here",editName.getText().toString());
b.putString("Passcode here",editPsscd.getText().toString());
b.putString("Sports here",editSport.getText().toString());
b.putString("Team here",editTeam.getText().toString());
intent.putExtra(b);
startActivity(intent);

将Success个活动注册到manifest.xml

进入成功活动获取Intent值

 Bundle b = getIntent().getExtras();
 String Name=b.getString("Name here"); 
 String Passcode=b.getString("Passcode here");
 String Sports=b.getString("Sports here");
 String Team =b.getString("Team here");

Answer 2

Intent intent = new Intent(this, DisplayMessageActivity.class);

使用Context作为其第一个参数（this，因为Activity类是Context的子类）

也改变了这个

public class Success extends GetIn

到

public class Success extends Activity

无法通过按钮单击使用Intent

2 个答案: