Question

我只想重新分配一行（来自同一张表）和新行1

该表的列'版本'为AI

其他三列（name，arrayV，notes）

CURRENT FAILED ATTEMPT（只是sql语法，使用固定值而不是变量）

UPDATE `variables` AS v1, `variables` AS v2 SET v1.`name` = v2.`name`, v1.`arrayV` = v2.`arrayV`, v1.`notes` = v2.`notes` WHERE v1.`version`=1,v2.`version`= 5;

以前失败的尝试

$newAI1 = $_POST["newSet"];//variable is an integer equal to another row ('version') in table
echo "New set of is ".$newAI1."<br/>";

$sqlMove = "INSERT INTO `variables` (`name`,`arrayV`,`notes`) WHERE `version` = '1' (SELECT `name`,`arrayV`,`notes` FROM `variables` WHERE `version` = '".$newAI1."')";

我哪里错了？

Answer 1

可能是这样的：

$sql = "update `variables` as v1, `variables` as v2 set v1.`name` = v2.`name`, ... where v1.`version`=1 and v2.`version`= '" .$newAI1 . "'"
$sqlDelete = "delete from `variables` where version='" . $newAI1. "'"

1）使用行$ newAI 1

中的值更新第1行

2）删除行$ newAI 1

将AutoIncrement mysql行替换为另一行

1 个答案: