我必须为linux-box编写一个脚本,它从命令行获取输入
sudo build_all.sh -vmware yes|no nic bridged|host_only -ipaddress xx.xx.xx.xx|dhcp -arch=ARM|x86
,我想知道输入输入时是否有办法我可以得到建议。
对于Ex。
如果我输入sudo build_all.sh
并按Tab
,我会在-vmware
再次输入我-vmware
Tab
之后获得Yes
之类的建议1}} No
。
有什么办法吗?
答案 0 :(得分:1)
这称为bash完成。您可以在/etc/bash_completion.d/中找到许多示例。 bash_completion函数需要先加载到shell中才能运行。这是一个让你入门的例子
# Bash completion must to be loaded when shell starts
# Recommended location is /etc/bash_completion.d/build_all.sh
# or added to ~/.bashrc
# Then load with . /etc/bash_completion.d/build_all.sh
# or with . ~/.bashrc
# New instances of bash will have already sourced it.
# The file name build_all.sh may be too common, and result in unwanted tab
# completion for build_all.sh from other projects.
_build_all.sh(){
local cur
COMPREPLY=()
_get_comp_words_by_ref cur
case $COMP_CWORD in
1) COMPREPLY=( $( compgen -W '-vmware' -- "$cur" ) ) ;;
2) COMPREPLY=( $( compgen -W 'no yes' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;
3) COMPREPLY=( $( compgen -W '-nic' -- "$cur" ) ) ;;
4) COMPREPLY=( $( compgen -W 'host_only bridged' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;
5) COMPREPLY=( $( compgen -W '-ipaddress' -- "$cur" ) ) ;;
6) COMPREPLY=( $( compgen -W 'dhcp xx.xx.xx.xx' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;
7) COMPREPLY=( $( compgen -W '-arch' -- "$cur" ) ) ;;
8) COMPREPLY=( $( compgen -W 'x86 ARM' -- "${COMP_WORDS[COMP_CWORD]}" ) ) ;;
esac
return 0
} &&
complete -F _build_all.sh build_all.sh
答案 1 :(得分:0)
有一个名为whiptail
的程序可以在文本模式下执行“GUI”对话框。