Question

我将以下列方式将一些数据插入到我的SQLite数据库中：

                  Contact contactData = new Contact();
                  contactData.setContact_id("1111");//String.valueOf(id)
                 //contactData.setNickName(name);
                 // contactData.setPrimaryContact(primary);

                  HashMap<String, Contact> map =  new  HashMap<String, Contact>();
                  map.put("data", contactData);

                  long newId = datasource.createContact(map);                     
                  Log.e("insert Contact id :", String.valueOf(newId));

和

public long createContact(HashMap<String, Contact> queryValues) {
ContentValues values = new ContentValues();

Contact val = (Contact) queryValues.get("data");

 values.put(  MySQLiteHelper.COLUMN_CONTACT_ID,  val.getContact_id());
values.put(  MySQLiteHelper.COLUMN_FIRST_NAME,  val.getFirstName());
values.put(  MySQLiteHelper.COLUMN_LAST_NAME, val.getLastName());
values.put(  MySQLiteHelper.COLUMN_NICK_NAME, val.getNickName());
values.put(  MySQLiteHelper.COLUMN_BIRTHDATE, val.getBirthDate());
values.put(  MySQLiteHelper.COLUMN_PRIMARY_CONTACT, val.getPrimaryContact());
values.put(  MySQLiteHelper.COLUMN_SECONDARY_CONTACT, val.getSecondaryContact());
values.put(  MySQLiteHelper.COLUMN_EMAIL_ID, val.getEmailId());
values.put(  MySQLiteHelper.COLUMN_STREET, val.getStreet());
values.put(  MySQLiteHelper.COLUMN_CITY, val.getCity());
values.put(  MySQLiteHelper.COLUMN_ZIP_CODE, val.getZipCode());
values.put(  MySQLiteHelper.COLUMN_COMPANY, val.getCompany());
values.put(  MySQLiteHelper.COLUMN_DESIGNATION,  val.getDesignation());
values.put(  MySQLiteHelper.COLUMN_IS_FAVORITE,  val.getIsFavorite());
values.put(  MySQLiteHelper.COLUMN_IS_BLOCKED,  val.getIsBloacked());    
values.put(  MySQLiteHelper.COLUMN_IS_CREATED,  new Date().toString());    
values.put(  MySQLiteHelper.COLUMN_IS_BLOCKED,  AESCryptography.getMd5(val.getFirstName()+" "+val.getLastName()+":"+val.getPrimaryContact()+":"+val.getEmailId()));   

long insertId = database.insert(MySQLiteHelper.CONTACT_TABLE_NAME, null, values);
return insertId;
}

但是我收到以下错误：

 02-06 17:13:18.539: E/SQLiteDatabase(8112): Error inserting lastName= contact_id=1111 primaryContact= street= designation= compnay= city= isCreated=Thu Feb 06 17:13:18 IST 2014 emailId= scondaryContact= nickName= isFavorite=0 zipCode= birthDate= firstName= isBloacked=�d�t�fVv�� ��
02-06 17:13:18.539: E/SQLiteDatabase(8112): android.database.sqlite.SQLiteConstraintException: error code 19: constraint failed
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.database.sqlite.SQLiteStatement.native_executeInsert(Native Method)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.database.sqlite.SQLiteStatement.executeInsert(SQLiteStatement.java:113)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1718)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.database.sqlite.SQLiteDatabase.insert(SQLiteDatabase.java:1591)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at com.ecosmob.contactpro.model.ContactDataSource.createContact(ContactDataSource.java:72)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at com.ecosmob.contactpro.service.ContactManagerService.onHandleIntent(ContactManagerService.java:88)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.app.IntentService$ServiceHandler.handleMessage(IntentService.java:65)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.os.Handler.dispatchMessage(Handler.java:99)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.os.Looper.loop(Looper.java:137)
02-06 17:13:18.539: E/SQLiteDatabase(8112):     at android.os.HandlerThread.run(HandlerThread.java:60)
02-06 17:13:18.539: E/insert Contact id :(8112): -1

我做错了什么？

我的表架构：

  private static final String CONTACT_TABLE = "create table "
  + CONTACT_TABLE_NAME + "(" 
  + COLUMN_ID                   + " integer primary key autoincrement, " 
  + COLUMN_CONTACT_ID           + " text not null, " 
  + COLUMN_FIRST_NAME           + " text not null,"
  + COLUMN_LAST_NAME            + " text not null,"
  + COLUMN_NICK_NAME            + " text not null,"
  + COLUMN_BIRTHDATE            + " text not null,"
  + COLUMN_PRIMARY_CONTACT      + " text not null,"
  + COLUMN_SECONDARY_CONTACT    + " text not null,"
  + COLUMN_EMAIL_ID             + " text not null,"
  + COLUMN_STREET               + " text not null,"
  + COLUMN_CITY                 + " text not null,"
  + COLUMN_ZIP_CODE             + " text not null,"
  + COLUMN_COMPANY              + " text not null,"
  + COLUMN_DESIGNATION          + " text not null,"
  + COLUMN_IS_FAVORITE          + " integer not null,"
  + COLUMN_IS_BLOCKED           + " integer not null,"
  + COLUMN_IS_CREATED           + " TIMESTAMP DEFAULT CURRENT_TIMESTAMP,"
  + COLUMN_CHECK_MD5            + " text not null"
  + ");";

Answer 1

你已经发表了大量的not null陈述。这意味着您需要在那里放置一些东西，否则数据库将拒绝新条目。我注意到你的insert语句中没有COLUMN_CHECK_MD5，这在你的模式中是必需的。看看是否还有其他人，并把东西放在那里。

Answer 2

您的列有NOT NULL个约束和18列，并且您尝试仅将值插入15列，如下所示：

Error inserting lastName= contact_id=1111 primaryContact= street= designation= compnay= city= emailId= scondaryContact= nickName=Bal Inquiry isFavorite=0 zipCode= birthDate= firstName= isBloacked=0

为每列添加值或从实际上为空的列中删除NOT NULL约束。

无法在Android中的SQLite中插入记录

2 个答案: